Answer:
a) The conditional probability of the deceased having had a standard policy = 0.6593
b) The conditional probability of the deceased having had a preferred policy = 0.2637
c) The conditional probability of the deceased having had an ultra preferred policy = 0.0769
Step-by-step explanation:
We are given that a life insurance company issues standard, preferred, and ultra preferred policies to it's policyholders.
Let Proportion of Policyholders having standard policies, P(
) = 0.6
Proportion of Policyholders having preferred policies, P(
) = 0.3
Proportion of Policyholders having ultra preferred policies, P(
) = 0.1
Now, D = event of policyholder dying next year
So, <em>Probability of policyholder dying given he had standard policies, </em>
<em> P(D/</em>
<em>) = 0.01.</em>
<em> Probability of policyholder dying given he had preferred policies, P(D/</em>
<em>) = </em>
<em> 0.008.</em>
<em> Probability of policyholder dying given he had ultra preferred policies, </em>
<em> P(D/</em>
<em>) = 0.007.</em>
Now using Bayes' Theorem we will find the required conditional probability;
The formula is given by, P(
/D) =
,where i goes from 1 to 3.
a) Probability of the deceased having had a standard policy given he died in the next year = P(
/D)
P(
/D) =
=
=
= 0.6593 .
b) Probability of the deceased having had a preferred policy given he died in the next year = P(
/D)
P(
/D) =
=
=
= 0.2637 .
c) Probability of the deceased having had a ultra preferred policy given he died in the next year = P(
/D)
P(
/D) =
=
=
= 0.0769 .