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Westkost [7]
3 years ago
8

A life insurance company issues standard, preferred, and ultrapreferred policies. Of the company’s policyholders of a certain ag

e, 60and a probability of 0.01 of dying in the next year, 30% have preferred policies and a probability of 0.008 of dying in the next year, and 10% have ultrapreferred policies and a probability of 0.007 of dying in the next year. A policyholder of that age dies in the next year. What are the conditional probabilities of the deceased having had a standard, a preferred, and an ultrapreferred policy?
Mathematics
1 answer:
Lilit [14]3 years ago
6 0

Answer:

a) The conditional probability of the deceased having had a standard policy = 0.6593

b) The conditional probability of the deceased having had a preferred policy = 0.2637

c) The conditional probability of the deceased having had an ultra preferred policy = 0.0769

Step-by-step explanation:

We are given that a life insurance company issues standard, preferred, and ultra preferred policies to it's policyholders.

Let Proportion of Policyholders having standard policies, P(A_1) = 0.6

     Proportion of Policyholders having preferred policies, P(A_2) = 0.3

     Proportion of Policyholders having ultra preferred policies, P(A_3) = 0.1

Now, D = event of policyholder dying next year

So, <em>Probability of policyholder dying given he had standard policies, </em>

<em>       P(D/</em>A_1<em>) = 0.01.</em>

<em> Probability of policyholder dying given he had preferred policies, P(D/</em>A_2<em>) = </em>

<em>  0.008.</em>

<em> Probability of policyholder dying given he had ultra preferred policies, </em>

<em> P(D/</em>A_3<em>) = 0.007.</em>

Now using Bayes' Theorem we will find the required conditional probability;

The formula is given by, P(A_k/D) = \frac{P(A_k)P(D/A_k)}{\sum_{i=1}^{m} P(A_i)P(D/A_i)} ,where i goes from 1 to 3.

a) Probability of the deceased having had a standard policy given he died in the next year = P(A_1/D)

   P(A_1/D) = \frac{P(A_1)P(D/A_1)}{ P(A_1)P(D/A_1)+P(A_2)P(D/A_2)+P(A_3)P(D/A_3)}

                = \frac{0.6\times 0.01}{0.6\times 0.01 + 0.3\times 0.008+0.1\times 0.007} = \frac{0.006}{0.0091} = 0.6593 .

b) Probability of the deceased having had a preferred policy given he died in the next year = P(A_2/D)

    P(A_2/D) = \frac{P(A_2)P(D/A_2)}{ P(A_1)P(D/A_1)+P(A_2)P(D/A_2)+P(A_3)P(D/A_3)}

                 = \frac{0.3\times 0.008}{0.6\times 0.01 + 0.3\times 0.008+0.1\times 0.007} = \frac{0.0024}{0.0091} = 0.2637 .

c) Probability of the deceased having had a ultra preferred policy given he died in the next year = P(A_3/D)

     P(A_3/D) = \frac{P(A_3)P(D/A_3)}{ P(A_1)P(D/A_1)+P(A_2)P(D/A_2)+P(A_3)P(D/A_3)}

                  = \frac{0.1\times 0.007}{0.6\times 0.01 + 0.3\times 0.008+0.1\times 0.007} = \frac{0.0007}{0.0091} = 0.0769 .

 

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