A mass is suspended on a vertical spring. Initially, the mass is in equilibrium. Then, it is pulled downward and released. The m
ass then moves up and down between the "top" and the "bottom" positions. By definition, the period of such motion is the time interval it takes the mass to move: Mark all the correct statements among those provided below. View Available Hint(s) Mark all the correct statements among those provided below. from the top position to the bottom. from the equilibrium position to the bottom. from the bottom position to the top. from the equilibrium position to the bottom and then back to the equilibrium. from the equilibrium position to the top and then back to the equilibrium. from the equilibrium position to the top. from the top position to the bottom and then back to the top. from the bottom position to the top and then back to the bottom.
As Time Period or periodic time period is time it takes to complete one complete cycle. So only these two options are correct. Yes ! If you assume a frictionless and isolated system then these two time intervals must be equal.
A mass is suspended on a vertical spring. Initially, the mass is in equilibrium. Then, it is pulled downward and released. The mass then moves up and down between the "top" and the "bottom" positions. By definition, the period of such motion is the time interval it takes the mass to move<em> from the top position to the bottom and then back to the top</em>, <u>OR</u><em> from the bottom position to the top and then back to the bottom</em>. The time for these two motions are nominally equal.
Venus is only 95% the size of Earth, and 81% of its mass. With the smaller size and mass, the force of gravity pulling you on the surface is lower. To get your weight on Venus, just multiply your current weight by 0.9. That's why 100 pounds becomes 90 pounds
