A stone is dropped from the edge of a roof. find the distance travelled by the stone in 2sec after its release.

1 answer:

3 0

S = ?
U = 0
V = ?
A = 9.81
T = 2

we tryna find s

lets use s = ut + (at^2)/2
ut cancels out since u = 0
(at^2)/2 = (9.81 x 2^2)/2
= 19.62m

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A metal ball attached to a spring moves in simple harmonic motion. The amplitude of the ball's motion is 11.0 cm, and the spring

german

Answer:

a)0.674 kg b) 2.2 s c) 0.9 m/s²

Explanation:

The amplitude of the ball (xo) = 11.0cm, half way between its equilibrium point its maximum displacement x = 11 cm / 2 = 5.5 cm = 5.5 / 100 in meters = 0.055 meters, speed at this point = 27.2 cm /s = (27.2 / 100) in m/s = 0.272 m/s,

spring constant K = 5.5 N/m

a) The mass of the ball (m) can be calculated using the formula below

v =√ (x²o - x²)K/m

make m subject of the formula

v² = (xo² - x²) K/m

m = K ( xo² - x²) / v²

m = 0.674kg

b) The period of the oscillation can be calculated by the following formula

T = 2π√ (m /K)

substitute the values into the formula

T = 2 × 3.142 × √ (0.674/ 5.5) = 2.2s

c) The maximum acceleration of the ball which occurs at the maximum displacement of the ball can be calculated by the following formula

a = K / m × x ( maximum displacement of the body) = 5.5 / 0.674 × 0.11 = 0.9 m/s²

7 0

3 years ago

The gravitational acceleration on Mars is 3.71 m/s2. If the pendulums were set in motion on the red planet, how would that affec

Elanso [62]

On Earth, the period of a pendulum is given by:
$T_{earth}=2\pi \sqrt{ \frac{L}{g_{earth} }$
where L is the length of the pendulum and $g_{earth}=9.81~m/s^2$ is the gravitational acceleration on Earth.
Similarly, the period of the same pendulum on Mars will be
$T_{mars}=2\pi \sqrt{ \frac{L}{g_{mars} }$
where $g_{mars}=3.71~m/s^2$ is the gravitational acceleration on Mars.
Therefore, if we want to see how does the period of the pendulum on Mars change compared to the one on Earth, we can do the ratio between the two of them:
$\frac{T_{mars}}{T_{earth}}= \sqrt{ \frac{g_{earth}}{g_{mars}} } = \sqrt{ \frac{9.81~m/s^s}{3.71~m/s^2} }=1.63$
Therefore, the period of the pendulum on Mars will be 1.63 times the period on Earth.

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4 years ago

A magnet that is dropped may lose its ______.

Nikitich [7]

Answer:

Permanent magnets can lose their magnetism if they are dropped or banged on enough to bump their domains out of alignment

Explanation:

3 0

3 years ago

A sleigh weighing 2000 newtons is pulled my a horse a distance of 1.0 kilometer (or 1000 meters) in 45 minutes. what is the powe

hoa [83]

Work = Force* Distance
2000*1000=2000000

Power = Work/Time

2000000/45=<span>44444.44 Watts</span>