Answer:
34.45m
Explanation:
Using the equation of motion formula v² = u²+2as to get the distance travelled
v is the final velocity = 26m/s
u is the initial velocity = 0m/s
a is the acceleration due to gravity = 9.81m/s²
S is the distance travelled
Substituting the given values into the formula;
26² = 0²+2(9.81)s
676 = 0 + 19.62s
19.62s = 676
s = 676/19.62
s = 34.45m
Hence the distance she would travel during the race is 34.45m
Answer:
Sporulation
the formations of spores from vegetative cells during unfavorable environmental conditions
Fragmentation
The asexual reproduction, where the body of the organism breaks into smaller pieces
Answer:
Explanation:
Impulse on an object is given by ![\mathrm{[impulse]}=F\Delta t](https://tex.z-dn.net/?f=%5Cmathrm%7B%5Bimpulse%5D%7D%3DF%5CDelta%20t)
.
However, it's also given as change in momentum (impulse-momentum theorem).
Therefore, we can set the change in momentum equal to the former formula for impulse:
.
Momentum is given by 
. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:
.
Now we plug in our values and solve:
(two significant figures).
Answer:
6.45×10¯²⁶ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 97.3 MHz
Energy (E) =?
Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:
1 MHz = 1×10⁶ Hz
Therefore,
97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz
97.3 MHz = 9.73×10⁷ Hz
Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.
Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:
Frequency (f) = 9.73×10⁷ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 9.73×10⁷
E = 6.45×10¯²⁶ J
Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J
