Answer:
1472.98 m
Explanation:
Data provided:
Speed of circular looping, v = 340 m/s
Acceleration, a = 8g
here,
g is the acceleration due to the gravity = 9.81 m/s²
Now,
the centripetal acceleration is given as,
r is the radius of the loop
on substituting the respective values, we get
or
r = 1472.98 m
Answer:
Electric switch is commonly known as the key of an electric circuit.
My response to question (a) and (b) is that all of the element of the rope need to aid or support the weight of the rope and as such, the tension will tend to increase along with height.
Note that It increases linearly, if the rope is one that do not stretch. So, the wave speed v= √ T/μ increases with height.
<h3>How does tension affect the speed of a wave in a rope?</h3>
The Increase of the tension placed on a string is one that tends to increases the speed of a wave, which in turn also increases the frequency of any given length.
Therefore, My response to question (a) and (b) is that all of the element of the rope need to aid or support the weight of the rope and as such, the tension will tend to increase along with height. Note that It increases linearly, if the rope is one that do not stretch. So, the wave speed v= √ T/μ increases with height.
Learn more about tension from
brainly.com/question/2008782
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See full question below
(a) If a long rope is hung from a ceiling and waves are sent up the rope from its lower end, why does the speed of the waves change as they ascend? (b) Does the speed of the ascending waves increase or decrease? Explain.
Answer:The term atomic number, conventionally denoted by the symbol Z, indicates number of protons present in the nucleus of an atom, which is also equal to the number of electrons in an uncharged atom. The number of neutrons is represented by the neutron number (N)
Explanation:
Hello!
First one we can use that PE=mgh so we have
4.37*10^5J/(9.12*10^3kg*9.80m/s^2)= 4.89m
Second one we can use Newton’s Second Law
F=ma and in this case F=mg so we have
g= 3.28*10^-2N/6*10^-3kg = 5.47m/s^2
Hope this helps. Any questions please ask. Thank you.
