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ANTONII [103]
3 years ago
15

a child sleds down a steep snow-covered hill with an acceleration of 3.94 m/s^2. if her initial speed is 0.0m/s and her final sp

eed is 21.1 m/s, how long does it take for her to travel from the top of the hill to the bottom?
Physics
1 answer:
-Dominant- [34]3 years ago
3 0

The time taken is 5.36 s

Explanation:

The motion of the child is a uniformly accelerated motion, therefore we can use the following suvat equation:

v=u+at

where

a is the acceleration

u is the initial  velocity

v is the final velocity

t is the time

For the child in this problem, we have:

u = 0

v = 21.1 m/s

a=3.94 m/s^2

Substituting and solving  for t,  we find the time taken:

t=\frac{v-u}{a}=\frac{21.1-0}{3.94}=5.36 s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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The dot or scalar product of two (3d) vec- tors ⃗a = ⟨a1,a2,a3⟩ and ⃗b = ⟨b1,b2,b3⟩ is defined as
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Yes, yes, we know all of that.  It certainly took you long enough to
get around to asking your question.

If
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and
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Their dot-product  a · b = (14 x 4.62) + (10.5 x 9.45) =

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I feel I earned your generous 5 points just reading your treatise and
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