1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fofino [41]
3 years ago
12

Which list correctly identifies each particle?

Physics
2 answers:
Temka [501]3 years ago
7 0

They want you to pick choice-A , but the whole question is poor and misleading.

The picture sorta kinda roughly presents the concept of the difference in MASSES ... one proton or one neutron has as much mass as about 1,840 electrons.

But things get very complicated on the scale of atoms and their components, and there's actually no such simple concept as the physical SIZE of any of these particles.

If ya wanna be absolutely technically correct, the picture is absurd, and the question has no answer.

LuckyWell [14K]3 years ago
5 0

Answer:

x represents an electron and y represents a proton and a neutron.

Explanation:

electrons are the smallest particle in an atom and protons and neutrons are a lot larger. thats why only protons and neutrons are weighed in atomic mass. electrons are too small to make a difference in the atom's weight.

You might be interested in
The metallic elements which all react in water are found in the:
MAXImum [283]
The metallic elements which all react to water are found in the same group, the groups name is the Alkali metals, or also known as group one. 
6 0
4 years ago
Read 2 more answers
A plane travels at a speed of 205mph in still air. Flying with a tailwind, the plane is clocked over a distance of 1000 miles. F
vaieri [72.5K]

While plane is moving under tailwind condition it took time "t"

so here we will have

t = \frac{d}{v_{net}}

here net speed of the plane will be given as

v_{net} = v + v_w

t = \frac{1000}{205 + v_w}

similarly when it moves under the condition of headwind its net speed is given as

v_{net} = v - v_w

now time taken to cover the distance is 2 hours more

t + 2 = \frac{1000}{205 - v_w}

now solving two equations

\frac{1000}{205 + v_w} + 2 = \frac{1000}{205 - v_w}

solving above for v_w we got

v_w = 40.4 mph

6 0
3 years ago
A large vessel of the diameter of 14 mm divides into two identical smaller vessels but the velocity of blood in
ycow [4]

Answer:

the diameter of the smaller vessels is 9.90 mm

Explanation:

The computation of the diameter of the smaller vessels is given below;

Given that

The larger vessel of the diameter is 14mm

So,

d1 = 7 mm

let us assume the diameter of the smaller artery is d2

Now we used the equation of continuity i.e.

v × pi × d1^2 = 2 × v × pi × d2^2

14^2 = 2 × d2^2

d2 = 9.90 mm

Hence, the diameter of the smaller vessels is 9.90 mm

5 0
3 years ago
A worker kicks a flat object lying on a roof. The object slides up the incline 10.0 m to the apex of the roof, and flies off the
11111nata11111 [884]

Answer:15.20 m

Explanation:

Given

initial velocity (v_i)=15 m/s

inclined length=10 m

\mu _k=0.435

inclination \theta =43.5^{\circ}

F_{net}=f_r+mg\sin \theta

a_{net}=\mu _kg\cos \theta +g\sin \theta

a_{net}=0.435\times 9.8\times \cos 43.5+9.8\times \sin 43.5

a_{net}=3.09+6.74=9.83 m/s^2

v^2-u^2=2as

v^2=15^2-2\times (9.83)10

v=5.31 m/s

So Particle launches with a speed of 5.31 m/s at an angle of \theta =43.5

h_{max}=\frac{u^2\sin^2\theta }{2g}

h_{max}=\frac{(5.31)^2\sin ^2(43.5)}{2\times 9.81}

h_{max}=0.679

Total height raised is 0.679+\frac{10}{\sin 43.5} =15.20 m

6 0
3 years ago
Skater 1 has a mass of 105.0 kg and a velocity of 2.0 m/s to the left. He
mart [117]

The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

<h3>What is velocity?</h3>

Velocity can be defined as the ratio of the displacement and time of a body.

To calculate the final velocity of Skater 1 we use the formula below.

Formula:

  • mu+MU = mv+MV............ Equation 1

Where:

  • m = mass of the first skater
  • M = mass of the second skater
  • u = initial velocity of the first skater
  • U = initial velocity of the second skater
  • v = final velocity of the first skater
  • V = final velocity of the second skater.

make v the subject of the equation.

  • v = (mu+MU-MV)/m................ Equation 2

Note: Let left direction represent negative and right direction represent positive.

From the question,

Given:

  • m = 105 kg
  • u = -2 m/s
  • M = 71 kg
  • U = 5 m/s
  • V = -3.4 m/s.

Substitute these values into equation 2

  • v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
  • v = (-210+355+241.4)/105
  • v = 386.4/105
  • v = 3.68 m/s
  • v ≈ 3.7 m/s

Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

Learn more about velocity here: brainly.com/question/25749514

7 0
2 years ago
Other questions:
  • The loop is in a magnetic field 0.20 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A
    9·1 answer
  • Which is a “big idea” of physical science? Motion cannot be altered by forces. Most of the mass of the Earth consists of solid m
    8·1 answer
  • 2/​A mains electricity hairdryer has a resistance of 46 Ω and a current of 5 A flows through it when in use. What is the voltage
    15·1 answer
  • ________ reaction time involves selecting a specific and correct response from several choices when presented with several diffe
    8·2 answers
  • Find the ratio of effusion rates of hydrogen gas and krypton gas.
    7·1 answer
  • Who does more work - a man who lifts a large box from the ground up into the back of a truck, or a man who puts the same box on
    8·1 answer
  • The least common shape for a galaxy is ______. irregular elliptical cluster spiral spherical
    14·2 answers
  • How much force would you need to cause a 20kg object to accelerate in a straight line to 20m/s2?
    15·1 answer
  • You grab a car door handle in the summer (energy transfer to heat up the handle ____) and it burns you through energy transfer.
    7·1 answer
  • A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to en
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!