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3 years ago

Which list correctly identifies each particle?

Physics

2 answers:

Temka [501]3 years ago

7 0

They want you to pick choice-A , but the whole question is poor and misleading.

The picture sorta kinda roughly presents the concept of the difference in MASSES ... one proton or one neutron has as much mass as about 1,840 electrons.

But things get very complicated on the scale of atoms and their components, and there's actually no such simple concept as the physical SIZE of any of these particles.

If ya wanna be absolutely technically correct, the picture is absurd, and the question has no answer.

LuckyWell [14K]3 years ago

5 0

Answer:

x represents an electron and y represents a proton and a neutron.

Explanation:

electrons are the smallest particle in an atom and protons and neutrons are a lot larger. thats why only protons and neutrons are weighed in atomic mass. electrons are too small to make a difference in the atom's weight.

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Which of the following is maintained across the terminals of a battery? A. a potential difference B. a voltage drop C. an electr

serious [3.7K]

I believe the answer is C. An electric charge

5 0

3 years ago

Read 2 more answers

Two equipotential surfaces surround a +1.70 x 10-8-C point charge. How far is the 120-V surface from the 54.0-V surface?

UNO [17]

Answer:

1.55 m

Explanation:

The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:

$V =\frac{k*q}{r}$

As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.

Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:

$r1 =\frac{k*q}{V1} = \frac{9e9 N*m2/C2*1.7e-8C}{120 V} = 1.28 m$

$r2 =\frac{k*q}{V2} = \frac{9e9 N*m2/C2*1.7e-8C}{54V} = 2.83 m$

The distance between both points, is just the difference between the radius of both spheres, as follows:

r₂ - r₁ = 1.55 m

5 0

3 years ago

a car traveling in a highway brakes to a stop without skidding. what happens to its kinetic energy? can that energy be recovered

docker41 [41]

Answer:

A car traveling on a highway takes to stop without skidding. What happens to its kinetic energy? ... The energy goes to parts of the brakes. No, the energy can only be reused if there is a heat pump present

7 0

3 years ago

Think of a sphere with many a star-

ycow [4]

Answer:

For it is a Globular Cluster

Explanation:

These Globular clusters are not considered to be a galaxies because they bond gravitationally to orbiting galaxies like the Milky Way and their masses are relatively small.

In globular clusters, the stars are closed together and they are like 70times closer to one another in their solar neighbourhood.

A globular cluster is a spherical collection of stars that orbits a galactic core. Globular clusters are very tightly bound by gravity, which gives them their spherical shapes, and relatively high stellar densities toward their centers.

3 0

3 years ago

A basketball player spins the ball with an angular acceleration of 10 rad/s2. What is the ball’s final angular velocity if the b

Lena [83]

Explanation:

It is given that,

The angular acceleration of the basketball, $\alpha=10\ rad/s^2$

Time taken, t = 3 seconds

We need to find the ball’s final angular velocity if the ball starts from rest. It can be calculated using definition of angular acceleration i.e.

$\alpha=\dfrac{\omega_f-\omega_i}{t}$

$\omega_i=0\ (rest)$

$\omega_f=\alpha t$

$\omega_f=10\ rad/s^2\times 3\ s$

$\omega=30\ rad/s$

So, the ball's final angular velocity is 30 rad/s. Hence, this is the required solution.

8 0

3 years ago