The metallic elements which all react to water are found in the same group, the groups name is the Alkali metals, or also known as group one.
While plane is moving under tailwind condition it took time "t"
so here we will have

here net speed of the plane will be given as


similarly when it moves under the condition of headwind its net speed is given as

now time taken to cover the distance is 2 hours more

now solving two equations

solving above for v_w we got

Answer:
the diameter of the smaller vessels is 9.90 mm
Explanation:
The computation of the diameter of the smaller vessels is given below;
Given that
The larger vessel of the diameter is 14mm
So,
d1 = 7 mm
let us assume the diameter of the smaller artery is d2
Now we used the equation of continuity i.e.
v × pi × d1^2 = 2 × v × pi × d2^2
14^2 = 2 × d2^2
d2 = 9.90 mm
Hence, the diameter of the smaller vessels is 9.90 mm
Answer:15.20 m
Explanation:
Given
initial velocity 
inclined length=10 m

inclination 







So Particle launches with a speed of 5.31 m/s at an angle of \theta 



Total height raised is 
The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.
<h3>What is velocity?</h3>
Velocity can be defined as the ratio of the displacement and time of a body.
To calculate the final velocity of Skater 1 we use the formula below.
Formula:
- mu+MU = mv+MV............ Equation 1
Where:
- m = mass of the first skater
- M = mass of the second skater
- u = initial velocity of the first skater
- U = initial velocity of the second skater
- v = final velocity of the first skater
- V = final velocity of the second skater.
make v the subject of the equation.
- v = (mu+MU-MV)/m................ Equation 2
Note: Let left direction represent negative and right direction represent positive.
From the question,
Given:
- m = 105 kg
- u = -2 m/s
- M = 71 kg
- U = 5 m/s
- V = -3.4 m/s.
Substitute these values into equation 2
- v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
- v = (-210+355+241.4)/105
- v = 386.4/105
- v = 3.68 m/s
- v ≈ 3.7 m/s
Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.
Learn more about velocity here: brainly.com/question/25749514