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Karo-lina-s [1.5K]
3 years ago
14

A computer is reading data from a rotating cd-rom. at a point that is 0.0130 m from the center of the disk, the centripetal acce

leration is 393 m/s2. what is the centripetal acceleration at a point that is 0.0884 m from the center of the disc?
Physics
1 answer:
likoan [24]3 years ago
6 0

The formula relating acceleration and angular velocity is:

a = ω^2 r

where a is acceleration, ω is angular velocity and r is radius

But the angular velocity ω is constant all throughout the disk therefore:

a1 / r1 = a2 / r2

 

So at points:

<span>r1 = 0.0130 m     -> a1 = 393 m/s^2</span>

<span>r2 = 0.0884 m     -> a2 = ?</span>

 

393 / 0.0130 = a2 / 0.0884

<span>a2 = 2,672.4 m/s^2</span>

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(b) To find the final velocity of the ice block at the end of the first 5 seconds,

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