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Karo-lina-s [1.5K]
3 years ago
14

A computer is reading data from a rotating cd-rom. at a point that is 0.0130 m from the center of the disk, the centripetal acce

leration is 393 m/s2. what is the centripetal acceleration at a point that is 0.0884 m from the center of the disc?
Physics
1 answer:
likoan [24]3 years ago
6 0

The formula relating acceleration and angular velocity is:

a = ω^2 r

where a is acceleration, ω is angular velocity and r is radius

But the angular velocity ω is constant all throughout the disk therefore:

a1 / r1 = a2 / r2

 

So at points:

<span>r1 = 0.0130 m     -> a1 = 393 m/s^2</span>

<span>r2 = 0.0884 m     -> a2 = ?</span>

 

393 / 0.0130 = a2 / 0.0884

<span>a2 = 2,672.4 m/s^2</span>

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How does the carbon rod of a cell beomes a positive<br>terminal?​
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Answer:

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Solve the following problem showing all work, the formula, and correct units.
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5g/cm³

it is not iron.

Explanation:

Given parameters:

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Unknown:

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Is it iron = ?

Solution:

The density of a substance is its mass per unit area. Every substance have an intensive density value that typifies them all.

The density of water and other substances are the same if they maintain their level of pureness.

   Density = \frac{mass }{volume}

Density of metal bar = \frac{2000}{400} = 5g/cm³

Since this value is not the same as the given density of iron, it is not iron.

learn more:

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8 0
3 years ago
Suppose we take a 1 m long uniform bar and support it at the 21 cm mark. Hanging a 0.40 kg mass on the short end of the beam res
Ipatiy [6.2K]

Answer:

The mass of the beam is = 29 kg.

Explanation:

A beam with mass 40 kg is shown in figure. Point S is the support point. Point B is the middle point on the beam where mass of the beam acts.

Taking moment about Point S

40 × 21 = M_{beam} × 29

M_{beam} = 29 kg

Therefore the mass of the beam is = 29 kg.

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2 years ago
Read 2 more answers
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