What is the math problem??
Knowing the power rule:
dx*n*x^(n-1) all you'd need to do is bring the 7 down and multiply it by -3, then subtract 1 from 7. Because dx is 1 you don't need to worry about it (you'll use chain rule for that)
So your final answer should be dy/dx= -21x^6
QN = 28
Solution:
Given MNPQ is a parallelogram.
QT = 4x + 6 and TN = 5x + 4
To find the length of QN:
Let us solve it using the property of parallelogram.
Property of Parallelogram:
Diagonals of the parallelogram bisect each other.
Therefore, QT = TN
⇒ 4x + 6 = 5x + 4
Arrange like terms together.
⇒ 6 – 4 = 5x – 4x
⇒ 2 = x
⇒ x = 2
Substitute x = 2 in QT and TN
QT = 4(2) + 6 = 14
TN = 5(2) + 4 = 14
QN = QT + TN
= 14 + 14
QN = 28
The length of QN is 28.
Answer:
2. 6/9
3.2/4
4. 8/10
Step-by-step explanation:
basically the idea is to find something in the same fact family so like the example on 1, follow that and try to answer the next problams on your own its really easy
( sorry if im wrong or not i tried to help)
Answer: 65.94 square meters
This value is approximate since pi = 3.14 is approximate
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Work Shown:
Area of circle = pi*(radius)^2
A = pi*r^2
Area of smaller circle = pi*2^2 <<--- replace r with 2; which is the smaller radius
Area of smaller circle = 4*pi
Area of larger circle = pi*5^2 <<--- replace r with 5 (since 3+2 = 5); which is the larger radius
Area of larger circle = 25*pi
Area of shaded region = (area of larger circle)-(area of smaller circle)
Area of shaded region = 25*pi - 4*pi
Area of shaded region = 21*pi
Area of shaded region = 21*3.14 <<--- replace pi with 3.14 (approximate)
Area of shaded region = 65.94 square meters
