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pentagon [3]
3 years ago
11

Square root of 9/100

Mathematics
1 answer:
timama [110]3 years ago
5 0
\sqrt{ \frac{9}{100} }
=\frac{3}{10}
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Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
Which number between 20 and 28 are prime
ad-work [718]
Prime numbers basically numbers that dont have any numbers that will be multiplied to get to it. So, it would be:
 23
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
All the other numbers in between can be divided by something and not become a decimal. Other than 23, it can be divided by anything without becoming a decimal.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
<em>~Hope this helped :)</em>
4 0
3 years ago
Read 2 more answers
Line segment BC will be reflected over line m to form line segment BC. Which of the following statements must be true?
Len [333]

Answer:

<u>Option A</u>

Step-by-step explanation:

To reflect line segment BC over line m, BB' will be perpendicular to the line m

and line m bisector of BB'.

<u>So, the correct answer is option A</u>

A) Line m is the perpendicular bisector of line segment BB' and the line segment CC'

<u>Option b is wrong</u> , it is impossible for the line B'C' to be perpendicular to line BC. B'C' is the image of BC.

<u>Both option c and d is wrong</u> because the perpendicular distance from b to the line m not equal to the perpendicular distance from c to the line m.

7 0
3 years ago
Is this statement true or false 5/12 = 2/6
AveGali [126]

Answer:

False

Step-by-step explanation:

6*2= 12

So to get common denominators, you would need to divide 5/12 by 2 OF multiply 2/6 by 2

For the sake of ease just multiply 2/6 by 2, this will equal 4/12 NOT 5/12

Hope this helps! :)

6 0
3 years ago
If 5 men paint a wall in 3hours,
nekit [7.7K]

Answer:20 men

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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