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Digiron [165]
3 years ago
10

Which system of linear inequalities has the point (3, –2) in its solution set?

Mathematics
2 answers:
denis23 [38]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

We want where  both inequalities are true

y > -3

-2 >-3  this is true

y ≥ 2/3x -4

-2≥ 2/3*3 -4

-2 ≥ 2 -4

-2≥ -2

This is true

This is is the graph

Gala2k [10]3 years ago
4 0

Answer:

\boxed{\sf Option \ 3}

Step-by-step explanation:

\sf The \ values \ must \ be \ true \ for \ both \ inequalities.

x = 3\\y = -2

y>-3\\-2>-3\\ \sf True

y\geq \frac{2}{3}x-4  \\ -2\geq \frac{2}{3}(3)-4\\2\geq 2-4\\-2\geq-2  \\ \sf True

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<h3>Difference of two squares</h3>

According to the question:

  • We are required to determine the equivalent expression.

When we try to factorise the given expression systematically; we have;

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