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Umnica [9.8K]
3 years ago
14

The spray from a lawn sprinkler makes a circle 40 feel in radius. What are the approximate diameter, circumference, and area of

the circle of lawn watered
Mathematics
1 answer:
Fittoniya [83]3 years ago
3 0
Our first step is to figure out what formulas are needed for diameter, circumference, and area of a circle.

Diameter is simply twice the size of the radius so:
2 * radius = 2 * 40 feet = 80 ft.

Circumference = 2 * pi * radius = 80 ft * pi 
If we say that pi = 3.14, then:
circumference = 251.2 ft.

Area = pi * radius^2 = pi * 1600 ft^2
Once again, if we assert pi = 3.14, then:
area = 3.14 * 1600 ft^2 = 5024 ft^2.
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event horizon

Step-by-step explanation:

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2 years ago
I need help with this question​
eimsori [14]

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2 years ago
A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment i
Tasya [4]

Answer:

(3,7) for the first line, and (12,0) for the second one.

Step-by-step explanation:

Hi Isabella,

1) The Midpoint of a line, when it comes to Analytical Geometry, is calculated as Mean of two points it follows:

x_{m}=\frac{x_{1} +x_{2} } {2}, y_{m} =\frac{y_{1}+ y_{2} }{2}

2) Each segment has two endpoints, and their midpoints, namely:

a) (1,-9) and its midpoint (2,-1)

b) (-2,18) and its midpoint (5,9)

3) Calculating. You need to be careful to not sum the wrong coordinates.

So be attentive!

The first line a

2=\frac{1+x_{2} }{2}\\  4=1+x_{2}\\  4-1=-1+1+x_{2} \\ x_{2}=3\\-1=\frac{y_{2}-9}{2}\\-2=y_{2}-9\\+2-2=y_{2}-9+2\\ y_{2}=-7

So (3,7) is the other endpoint whose segment starts at (1,-9)

The second line b endpoint at (-2,18) and its midpoint (5,9)

5=\frac{-2+x_{2} }{2} \\ 10=-2+x_{2} \\ +2+10=+2-2+x_{2}\\ x_{2}=12 \\ \\ 9=\frac{18+y_{2} }{2} \\ 18=18+y_{2} \\ -18+18=-18+18+y_{2}\\ y_{2} =0

So (12,0) it is the other endpoint.

Take a look at the graph below:

8 0
3 years ago
How dose north america achieve 480VAC with 3 pole 120VAC
makvit [3.9K]

Answer:

There are a variety of factors driving the

adoption of 415/240VAC distribution. First,

distributing at these increased voltages

enables overall efficiency to be enhanced

by eliminating the need for a voltage

transformation along the power path. For

example, in a 415V system, the L-N voltage

is 240V, which is compatible with most all IT

loads. By shifting the UPS output distribution

voltage to 415/240 V three-phase (L-L/

L-N), most of the existing servers today can

be powered with 240V single-phase (L-N)

without any intermediate transformation.

Removing the need for a transformer

streamlines the power path and can increase

efficiency approximately 1.5 percent.

The adoption of a 415/240VAC distribution

model also can yield additional savings at

the device-level in the form of increased

efficiency for server power supplies. As

previously mentioned, today’s power

supplies can handle a wide range of incoming

voltages. Based on the actual voltage being

fed into the power supply, efficiencies can

range from as low as 80 percent (at 100V

nominal) to as much as 94 percent (at 240V

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Furthermore, while the typical efficiency

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at the server power supply today is a relatively

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between 240V and 120V servers can be as

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It is this value that often gets overstated by

some manufacturers when comparing 415V

distribution to “traditional methods,” as

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Step-by-step explanation:

7 0
3 years ago
Can someone help solve 1 + 2x = 7?​
Yanka [14]

Answer:

3

Step-by-step explanation:

1+2x=7

7-1=6

2x=6

6/2=3

x=3

5 0
3 years ago
Read 2 more answers
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