(3a²+6ab-24²)= 3a(a+2b)x(4b)
Answer:
the ratio of the following x is 3/4
Answer:
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Step-by-step explanation:
least of 3 consecutive integers is a, and the greatest is z
if a is the least one
we know that integers differ by value of 1.
example -2, -1, 0, 1,2
they all differ by
then next consecutive integer will be a+1
third integer will be second integer +1 = a+1 + 1 = a+2
Thus, 3 consecutive integer
a , a+1, a+2
but given that greatest is z
thus, a+2 is greatest and hence
a+2 = z
we have to find value of a + 2z/ 2 in terms of a
a + 2z/ 2 = a + 2(a+2)/2 = (a+ 2a +4)/2 = (3a+4)/2.
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Answer:
c
Step-by-step explanation:
math
Mine is pretty rough but hope it helps look at the attached image.
