Use the rules of logarithm:
1. log(x)+log(y)=log(xy)
log(x)-log(y)=log(x/y)
2. k*log(x) = log(x^k)
log(x)/k = log(x^(1/k))
<span>log(2z)+2log(2x)+4log(9y)+12log(9x)−2log(2y)
=</span>log(2z)+log(4x^2)+log(9^4y^4)+log(9^12x^12)−log(4y^2)
=log(2z)+log(4x^2)+log(6561y^4)+log(282429536481x^12)−log(4y^2)
=log(59296646043258912 * x^14 * y^6 * z)
The cost price of the table is $40.
<h3>What is Gain ?</h3>
Gain is the amount gain by selling the product at a higher price than its cost.
Let the cost of the table is $ x
The percentage gain is x% (as given in the question)
Cost price = ?
It is known that
Step 1 : Gain = ( selling Price - Cost Price) * 100 / Cost Price
Selling price = 56
Cost Price = $ x
Therefore substituting the value
x = (56 - x) * 100 / x
x² = 5600 - 100x
x² +100x -5600 = 0
Step 2 : Factorizing
x² + 140x - 40 x -5600 = 0
x( x+14 ) -40( x +14) = 0
( x - 40)(x +14) = 0
x = $40
Therefore the cost price of the table is $40.
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Answer:
3.48cm³ (approximated)
Step-by-step explanation:
The maximum water that bowl can hold = The volume of the bowl
Radius is half of diameter.
<u>Given</u> -
<em>From</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>data</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>derive </em><em>that</em><em> </em><em>the</em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>hemispheri</em><em>cal</em><em> </em><em>bowl</em><em> </em><em>is</em><em> </em><em>5</em><em>c</em><em>m</em><em> </em><em>(</em><em>1</em><em>0</em><em>/</em><em>2</em><em>)</em>
Putting the known values into the formula to get the value of the volume of bowl :
= 3.48888cm³
= 3.48cm³
We can make an equation that would help this. X will be the discount rate.
4x=3.60
Now, we need to solve the equation to find what X is.
Let's divide each side by 4.
x=.9
So, we know that the item was sold for 90% of what it was before, meaning that it has a 10% discount.
