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3 years ago

6

explain why you are always accelerating when you ride a merry go round even though the speed of the merry go round does not chan

ge?

1 answer:

Artemon [7]3 years ago

5 0

Because you are constantly changing direction it means there is a constant force acting on you and that means you are accelerating.

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You are looking down on a N = 9 turn coil in a magnetic field B = 0.5 T which points directly down into the screen. If the diame

Novay_Z [31]

Answer:

The magnitude of the voltage is $2.27\times10^{-4}\ V$ and the direction of the current is clockwise.

Explanation:

Given that,

Number of turns = 9

Magnetic field = 0.5 T

Diameter = 3 cm

Time t = 0.14 s

We need to calculate the flux

Using formula of flux

$\phi=NAB$

Put the value into the formula

$\phi=9\times\pi\times(1.5\times10^{-2})^2\times0.5$

$\phi=0.003180$

We need to calculate the emf

Using formula of emf

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{0.003180}{0.14}$

$\epsilon =-0.000227\ V$

$\epsilon=-2.27\times10^{-4}\ V$

Negative sign shows the direction of current.

Hence, The magnitude of the voltage is $2.27\times10^{-4}\ V$ and the direction of the current is clockwise.

8 0

3 years ago

Benny wants to estimate the mean lifetime of Energizer batteries, with a confidence level of 97%, and with a margin of error not

VikaD [51]

Answer:

143 batteries does Benny need to sample

Explanation:

Given data

confidence level = 97%

error = ±10 hours

standard deviation SD = 55 hours

to find out

how many batteries does Benny need to sample

solution

confidence level is 97%

so a will be 1 - 0.97 = 0.03

the value of Z will be for a 0.03 is 2.17 from standard table

so now we calculate no of sample i.e

no of sample = (Z× SD/ error)²

no of sample = (2.16 × 55 / 10)²

no of sample = 142.44

so 143 batteries does Benny need to sample

7 0

2 years ago

An object with a mass of 1.5 kg accelerates 10.0 m/s2? when an unknown force is applied to it. What is the amount of the force?

Svetlanka [38]

Answer:

15N

Explanation:

f=ma

1.5kg x 10m/so

f= 15N

7 0

2 years ago

A test charge is placed at a distance of 2.0 × 10-1 meters from a charge of 5.4 × 10-8 coulombs. What is the electric field at t

Alborosie

The electric field E of a charge is defined as E=F/Q where F is the Coulomb force and Q is the test charge.

E=(1/Q)*k*(q*Q)/r², where k=9*10^9 N*m²/C², q is the point charge, Q is the test charge and r is the distance between the charges.

So E=(k*q)/r²

When we input the numbers we get that electric field E of a point chage q is:

E=(9*10^9)*(5.4*10^-8)/0.2²=486/0.04=12150 N/C.
This is roughly E=12000 N/C =1.2*10^4 N/C
The correct answer is B.

6 0

2 years ago

Read 2 more answers

You machine that tells you exactly how much work in joules is put into a machine and how much work produced. The reading that yo

marysya [2.9K]

Friction in the machine turned 15 joules of the energy input into heat. If you were monitoring the parts of the machine closely, you would notice that some of them warmed up.

7 0

2 years ago