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3 years ago

If a bullet travels at 551.0 m/s, what is its speed in miles per hour?

1 answer:

6 0

<span>First, convert meters into feet. One meter = 3.28 feet. Next, convert meters per second to feet per second. 551.0 m/s = 1,807.28 ft/sec. Now using the knowledge that 5280 ft = 1 mile and there are 3600 seconds in an hour; convert 1,807.28 ft/sec into miles per hour. The final answer to the question is 1,232.24 miles per hour.</span>

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The magnetic quantum number of an electron (m) designates the:

inessss [21]

I think the correct answer from the choices listed above is the third option. The magnetic quantum number of an electron (m) designates the orientation in space of the orbital (electron cloud). <span>This number divides the subshell into individual orbitals which hold the electrons; there are 2l+1 orbitals in each subshell. </span>

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4 years ago

A truck travels 6 meters in the first second of travel, 6 meters again during another second of travel, and 6 meters again durin

Alexandra [31]

D. Assuming that it doesn’t accelerate and then decelerate between seconds.

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3 years ago

Energy cannot be _________ or ___________ just ______________ in form.

djverab [1.8K]

Answer: Energy cannot be <u>created</u> or <u>destroyed</u> just <u>changes</u> in form.

Explanation:

This is the principle of the first Law of Thermodynamics, which relates the work and the transferred energy exchanged in a system through the internal energy, which is neither created nor destroyed, it is only transformed.

In other words: The total energy of a system is always conserved.

7 0

4 years ago

A solenoidal coil with 25 turns of wire is wound tightly aroundanother coil with 300 turns. The inner solenoid is 25.0 cm long a

Aneli [31]

Answer:

(a). The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Explanation:

Given that,

Number of turns of coil = 25

Number of turns of another coil = 300

Length = 25.0 cm

Diameter = 2.00 cm

Current = 0.120 A

Rate $\dfrac{di_{2}}{dt}=1.75\times10^{3}\ A/s$

(a). We need to calculate the magnetic field due to inner solenoid

Using formula of magnetic field

$B=\mu_{0}(\dfrac{N_{2}}{l})I$

Put the value into the formula

$B=4\pi\times10^{-7}\times(\dfrac{300}{0.25})\times0.120$

$B=1.81\times10^{-4}\ T$

We need to calculate the average magnetic flux through each turn of the inner solenoid

Using formula of magnetic flux

$\phi=B\cdot A$

Put the value into the formula

$\phi=1.81\times10^{-4}\times\pi\times (1.00\times10^{-2})^2$

$\phi=5.68\times10^{-8}\ Wb$

The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). We need to calculate the mutual inductance of the two solenoids

Using formula of mutual inductance

$M=\dfrac{N_{1}\phi}{i_{1}}$

Put the value into the formula

$M=\dfrac{25\times5.68\times10^{-8}}{0.120}$

$M=0.00001183\ H$

$M=1.183\times10^{-5}\ H$

The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). We need to calculate the emf induced in the outer solenoid by the changing current in the inner solenoid

Using formula of emf

$\epsilon=-M\dfrac{di_{2}}{dt}$

Put the value into the formula

$\epsilon=-1.183\times10^{-5}\times1.75\times10^{3}$

$\epsilon=-0.0207\ V$

The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Hence, (a). The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

5 0

3 years ago

two identical waves of amplitude 5cm meet in a large ripple tank what will be the aplitude of the combined wave at a point where

timofeeve [1]

(a) For constructive interference the two waves will have higher amplitude of 10 cm.

(b) For destructive interference the two waves will have zero amplitude.

<h3>Amplitude of the waves for constructive interference </h3>

For constructive interference the two waves will have higher amplitude after constructive interference.

Resulting amplitude = 5 cm + 5cm = 10 cm

<h3>Amplitude of the waves for destructive interference </h3>

For destructive interference the two waves will have zero amplitude after destructive interference.

Resulting amplitude = 5 cm - 5cm = 0

Learn more about amplitude here: brainly.com/question/413740

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4 0

3 years ago