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Leno4ka [110]
3 years ago
9

Evaluate x and y in the equation: E=Cm^xV^y , where E is kinetic energy , m is mass , V is velocity and C is a dimension less co

nstant
Physics
1 answer:
Korvikt [17]3 years ago
8 0

Answer: Do I look like Einstein

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One of the harmonics of a string fixed at both ends has a frequency of 52.2 Hz and the next higher harmonic has a frequency of 6
Angelina_Jolie [31]

Solution :

Frequency may be defined as the number of observation or number of waves that is taken in per unit time. The unit of frequency is Hertz or Hz.

It is given that :

Successive harmonic frequencies, f = 52.2 Hz

and f' = 60.9 Hz

Therefore, fundamental frequency, F = f' - f

                                                           F = 60.9 - 52.2

                                                          F = 8.7 Hz

Therefore the string which is fixed at both the ends forms all the harmonics.

6 0
3 years ago
Where is the potential energy equal to zero?
s2008m [1.1K]

Answer:

im sure your already past this but it's E.

Explanation:

This is because in this case potential energy is linear to height, which means that the higher the more potential energy.

4 0
3 years ago
Multiplying or dividing vectors by scalar results in?
Minchanka [31]
You divide sort of the similar but vector is distance and displacement and scalar is just distance
6 0
3 years ago
A 20,000 kg truck traveling at 25 m/s has a head-on inelastic collision with a 1500 kg car traveling at -30 m/s. calculate the i
tankabanditka [31]
Moment is mass times speed
INITIAL moment before collision was 20 000 times 25 = 500 000
7 0
3 years ago
A spring with a spring constant of 1200 N/m has a 55-g ball at its end. The energy of the system is 5.5J. What is the amplitude
Pepsi [2]
The energy of the system is E=5.5 J. This energy is the  same at every moment of the oscillation. When the stretch x of the spring is maximum (so, when the stretch is equal to the amplitude: x=A) the velocity of the spring is zero, so all this energy is just elastic potential energy of the spring:
E= \frac{1}{2}kA^2
From which we find
A= \sqrt{ \frac{2E}{k} }= \sqrt{ \frac{2 \cdot 5.5 J}{1200 N/m} }=0.096 m
4 0
3 years ago
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