Work = Force * distance
Work = 40N * 10m
Work = 400N
Answer:
3 m/s
Explanation:
Initial = Final
Mass * Velocity = Mass *Velocity
8000kg * 12m/s = (8000kg+ 24000kg) * (Final Velocity)
(96000 kgm/s) / (32000kg) = (Final Velocity)
Final Velocity = 3 m/s
I think that when work is done and a force istransferred an object must move in the direction of the force.
Answer:
The total frictional force is 358.0 newtons
Explanation:
Power is the amount of average work (W) an object does on a period of time (Δt):
Remember average work is average force (F) times displacement (Δs):
but displacement over time is average speed , then:
(1)
That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:
Knowing that 1hp is 746W then 30hp=22380W and 1 mile = 1609m then 140 mph = 225308 = , then:
The answer is 2.66 x 10^8 J.