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ELEN [110]
3 years ago
14

Use a metric prefix to write 3,100 grams in kilograms

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

3.1 kg

Step-by-step explanation:

3100 × 10^-3 = 3.1

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1. Evan drove 308 km in the same time that Meghan drove 329 km. If Meghan drove
emmainna [20.7K]

Answer:

Her average speed is 94 km/h

Time taken is 3.5 hours

Step-by-step explanation:

Let Evan’s average speed be x km/h.

now since Meghan drove faster, according to the question, we can say her average speed would be x + 6 km/h

Mathematically, time = distance/speed

so; since time is the same; we have

308/x = 329/(x + 6)

cross multiply

329(x) = 308(x + 6)

329x = 308x + 1848

329x-308x = 1848

21x = 1848

x = 1848/21

x = 88 km/h

Meghan average speed = x + 6 = 88 + 6 = 94 km/h

Time taken would be 329/94 = 3.5 hours

8 0
3 years ago
Given that
valentina_108 [34]

Answer: x= -3.25

Step-by-step explanation:

R=4x+6y   11=4x+6(4)     11=4x+ 24     11-24=4x   -13=4x  -13/4=x  x=-3.25

11=4(-3.25)+ 6(4)  11= -13+24

6 0
3 years ago
Which sequence of transformations maps pre-image ABC to
matrenka [14]

Triangle ABC was reflected over the y-axis and  then translated 2 units up and 2 units to the right

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

Translation is the movement of a point up, down, left or right. If a point A(x, y) is translated b units up and a units to the right, the new point is A'(x + a, y + b).

Reflection is the flipping of a figure. If a point A(x, y) is reflected along the y axis the new point is A'(-x, y).

Triangle ABC is at A(1, 2), B(4, 6) and C(7, 3). If it is reflected over the y-axis, the new point is A*(-1, 2), B*(-4, 6) and C*(-7, 3). If it is then translated 2 units up and 2 units to the right, the new image is:

A'(1, 4), B'(-2, 8) and C'(-5, 5)

Hence, Triangle ABC was reflected over the y-axis and  then translated 2 units up and 2 units to the right

Find out more at: brainly.com/question/11707700

3 0
3 years ago
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
The Perpendicular to Parallels Theorem is based on
nirvana33 [79]
Two lines that meet to form congruent adjacent angles.
4 0
3 years ago
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