60/48
Both can be reduced by 12 to 5/4
So you can have 12 groups with 5 6th graders and 4 7th graders
Figures of same shape and size are similar .Two circles C1&C2 will be similar.
Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y is having a translation of y-4.The center of the circle is dilated by 3 units.
The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.
2) Area of sector = ÷360.
Where α is the angle made at center.
Area of given sector= π(12)(12)(60)÷360 =24π.
5) So for parallelogram ABCD, ∠B ≅ ∠D, and ∠A ≅ ∠C. Further, ∠B and ∠A are supplementary (i.e., their sum is 180°), and ∠D and ∠C are also supplementary.
So, we have that m∠B = m∠D. Therefore,
Now, let's substitute for x back into the expression for either ∠B or ∠D to find it's angle measure.
m∠B =
Now, remember that ∠B or ∠D are supplements of ∠A.
So, m∠B + m∠A = 180°.
That means m∠A = 180° – 72° = 108°.
That seems reasonable, because A appears to be an obtuse angle.