Answer? i rlly dont know

The acid desert of the business on the March 31 2015 are worth rupees 500000 and its capital is rupees 350000 and its liabilitie

kifflom [539]

Assets = Liabilities + Capital

Liabilities = Assets - Capital

Liabilities = 50,000 - 35000

Liabilities = 15,000

5 0

2 years ago

Factor completely 4x2 − 8x − 60. (4x − 20)(x + 3) 4(x − 5)(x + 3) (4x − 4)(x + 15) 4(x − 1)(x + 15)

katovenus [111]

after complete factorization of $4x^2-8x-60$ the answer is $4(x+3)(x-5)$

Step-by-step explanation:

We need to factor $4x^2-8x-60$

Taking 4 common and factorizing:

$=4(x^2-2x-15)\\=4(x^2+3x-5x-15)\\=4(x(x+3)-5(x+3))\\=4(x+3)(x-5)$

So, after complete factorization of $4x^2-8x-60$ the answer is $4(x+3)(x-5)$

Keywords: factorization, factors

Learn more about factors at:

#learnwithBrainly

3 0

2 years ago

Each regular polygon has radil and apothem as shown. Find the measure of each numbered angle.

ruslelena [56]

Answer:

∠5 = 60°

∠6 = 30°

∠7 = 120°

Step-by-step explanation:

Since the polygon is regular, you know that the central angle (7) is 1/3 of the circle, or 120°. The angle 5 is half that measure, so is 60°, and the angle 6 is the complement of angle 5, so is 30°. (Angle 6 is also half the inscribed angle at each vertex, said inscribed angle being 120°/2 = 60°.)

∠5 = 60°

∠6 = 30°

∠7 = 120°

4 0

1 year ago

200 slices divided by 16 slices per tomato was he

Virty [35]

200 / 16 = 12.5

i think is the answer

6 0

2 years ago

Read 2 more answers

Teacher raises A school system employs teachers at

Cerrena [4.2K]

By adding a constant value to every salary amount, the measures of

central tendency are increased by the amount, while the measures of

dispersion, remains the same

The correct responses are;

(a) The shape of the data remains the same

(b) The mean and median are increased by $1,000

(c) The standard deviation and interquartile range remain the same

Reasons:

The given parameters are;

Present teachers salary = Between $38,000 and $70,000

Amount of raise given to every teacher = $1,000

Required:

Effect of the raise on the following characteristics of the data

(a) Effect on the shape of distribution

The outline shape of the distribution will the same but higher by $1,000

(b) The mean of the data is given as follows;

$\overline x = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i}$

Therefore, following an increase of $1,000, we have;

$\overline x_{New} = \dfrac{\sum (f_i \cdot (x_i + 1000))}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i + f_i \cdot 1000))}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + \dfrac{\sum (f_i \cdot 1000)}{\sum f_i}$

$\overline x_{New} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + \dfrac{\sum (f_i \cdot 1000)}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + 1000 = \overline x + 1000$

Therefore, the new mean, is equal to the initial mean increased by 1,000

Median;

Given that all salaries, $x_i$ , are increased by $1,000, the median salary, $x_{med}$ , is also increased by $1,000

Therefore;

The correct response is that the median is increased by $1,000

(c) The standard deviation, σ, is given by $\sigma =\sqrt{\dfrac{\sum \left (x_i-\overline x \right )^{2} }{n}}$ ;

Where;

n = The number of teaches;

Given that, we have both a salary, $x_i$ , and the mean, $\overline x$ , increased by $1,000, we can write;

$\sigma_{new} =\sqrt{\dfrac{\sum \left ((x_i + 1000) -(\overline x + 1000)\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x - 1000\right )^{2} }{n}}$

$\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x - 1000\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}}$

$\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}} =\sqrt{\dfrac{\sum \left (x_i-\overline x \right )^{2} }{n}} = \sigma$

Therefore;

$\sigma_{new} = \sigma$ ; The standard deviation stays the same

Interquartile range;

The interquartile range, IQR = Q₃ - Q₁

New interquartile range, IQR $_{new}$ = (Q₃ + 1000) - (Q₁ + 1000) = Q₃ - Q₁ = IQR

Therefore;

The interquartile range stays the same

Learn more here:

brainly.com/question/9995782

6 0

2 years ago