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Mathematics

1 answer:

Gnesinka [82]2 years ago

3 0

Answer:

Step-by-step explanation:

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A loan for $1,200 has an annual interest rate of 5.2%. There is a $15 processing fee to receive the loan. The loan’s APR is .

Charra [1.4K]

<u>Answer: </u>

A loan for $1,200 has an annual interest rate of 5.2%. There is a $15 processing fee to receive the loan. The loan’s APR is 5.2%

<u>Solution: </u>

Since full form of APR is Annual Percentage Rate and it is defined as rate of interest for whole year which means it is same as annual interest rate. Also processing fee is totally different component.

So APR = annual interest rate ----- eqn 1

Given that a loan of $1200 has an annual interest rate of 5.2% .

So by using eqn 1 we can say APR = annual interest rate = 5.2%

Hence APR for a loan of $1200 is 5.2%

6 0

3 years ago

If a procedure meets all of the conditions of a binomial distribution except the number of trials is not fixed, then the geomet

natima [27]

Answer:

Given p = 0.07 as the probability that someone is a universal donor

In case of Geometric Distribution, Probability of getting the first success on nth trial is given by

$P (X=n) = p (1-p) ^ {n-1}$

where p is the probability of success on any one trial and (1-p) shows the probability of failure.

So the probability of the first subject to be a universal blood donor will be the seventh person is

$P (X=7) = 0.07 (1-0.07) ^ {7-1} = 0.07 (0.93) ^ 6 = 0.07*0.647 = 0.0453$

So the final probability is 0.0453

3 0

3 years ago

A criminal has escaped in a train wreck. The police believe he could have traveled no more than 7 mi in any direction from the w

adelina 88 [10]

Answer:

A = 153.94 sq mi

Step-by-step explanation:

In this scenario, we would be starting from the center point and searching the area of a square since the distance in every direction would the same 7 mi. This 7-mile distance would be our radius in this scenario. We now need to use the formula for the Area of a circle to calculate the search area. This formula is the following

A = $\pi r^{2}$