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Greeley [361]
3 years ago
10

Convert 386 milligrams to grams. 0.386 g 3.86 g 38.6 g 3,860 g

Mathematics
1 answer:
34kurt3 years ago
6 0
G= mg/1000 
x g= 386mg/1000
x = 0.386g
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You are the foreman of the Bar-S cattle ranch in Colorado. A neighboring ranch has calves for sale, and you are going to buy som
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Answer:

When you have two sets of data, one that represents an independent variable (X) and another that represents a dependent variable (Y) (it is a response of the first variable). A diagram called scatterplot can be generated to present the ordered pairs (X, Y) in the Cartesian plane to see how the two variables are related.

In this case the independent variable (X) is the age variable of the calf and the dependent variable (Y) is the weight of the calf.

The diagram can be seen in the attached file.

Step-by-step explanation:

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12 lb13 oz + 6 lb11 oz
max2010maxim [7]

Answer:

19 lbs and 8 oz

Step-by-step explanation:

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3 years ago
What is the slope of the line (-4,-4) and (1,4)
Misha Larkins [42]

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8/5

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7 0
3 years ago
Read 2 more answers
Any help would be appreciated. Thank you!
trapecia [35]

Answer:

Area =62.5\sqrt{6} square units

AB=5\sqrt{15} units

BC=5\sqrt{10} units

Step-by-step explanation:

In a right triangle the altitude drawn to the hypotenuse is the geometric mean of the segments at which this altitude divides the hypotenuse.

So,

BD^2=15\cdot 10\\ \\BD^2=150\\ \\BD=\sqrt{150}=5\sqrt{6}\ units

a. The area of the triangle ABC is

A_{ABC}=\dfrac{1}{2}\cdot BD\cdot AC=\dfrac{1}{2}\cdot 5\sqrt{6}\cdot (15+10)=\dfrac{125\sqrt{6}}{2}=62.5\sqrt{6}\ un^2.

b. The legs of the right triangle are geometric means of the segment adjacent to this leg and the hypotenuse, so

AB^2=AD\cdot AC=15\cdot 25\Rightarrow AB=5\sqrt{15}\ units\\ \\BC^2=CD\cdot AC=10\cdot 25\Rightarrow BC=5\sqrt{10}\ units

5 0
3 years ago
F(x) = (4x–5)/6 <br> Find the Inverse
noname [10]

Answer:

F^-1 (x) = 3x/2+5/4

Step-by-step explanation:

First, replace f(x) with y

Replace every x with a y and replace every y with an x .

Solve the equation from Step 2 for y  

Replace y with f−1(x) f − 1 ( x )

Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.

Hope this helps!  Stay Safe!

3 0
3 years ago
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