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trasher [3.6K]
3 years ago
7

Part a what are the electron and molecular geometries, respectively, for the carbonate ion, co3 2−?

Chemistry
1 answer:
san4es73 [151]3 years ago
4 0

The electronic geometry for the carbonate ion, in CO₃²⁻ is trigonal planar, and molecular geometry will be trigonal planar.

The electronic geometry = Total number of atoms + lone pair around the central atom

= 3 atoms + 0 lone pair

= sp₂ (trigonal planar)

The molecular geometry = As there is no lone pair its geometry will be trigonal planar.

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A tank containing methanol has walls 2.50 cm thick made of glass of refractive index 1.550. Light from the outside air strikes t
anyanavicka [17]

18.6

use snells law for glass n=sini/sinr

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4 0
3 years ago
A 136 g sample of an unknown substance was heated from 20.0 °C to 40.0 °C. In the process the substance absorbed 2440 J of energ
Julli [10]

Answer:

Option A. The specific heat is 0.897 J/gºC, The Substance is aluminum.

Explanation:

We'll begin by calculating the change in temperature of the substance. This can be obtained as follow:

Initial temperature (T₁) = 20.0 °C

Final temperature (T₂) = 40.0 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 40 – 20

ΔT = 20 °C

Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:

Mass (M) = 136 g

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 2440 J

Specific heat capacity (C) =?

Q = MCΔT

2440 = 136 × C × 20

2440 = 2720 × C

Divide both side by 2720

C = 2440 / 2720

C = 0.897 J/gºC

Comparing the specific heat capacity (i.e 0.897 J/gºC) of the substance with those in the table above, the substance is Aluminum.

Thus, option A gives the correct answer to the question.

4 0
3 years ago
How is the structure of the atom arranged?
In-s [12.5K]

Answer:

An atom is a complex arrangement of negatively charged electrons arranged in defined shells about a positively charged nucleus. This nucleus contains most of the atom's mass and is composed of protons and neutrons (except for common hydrogen which has only one proton).

Explanation:

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Under what categories of cells would the animal and plant cell fall
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6 0
4 years ago
A sample of helium gas has a volume of 1.50 L at 159 K and 5.00 atm. When the gas is compressed to 0.200 L at 50.0 atm, the temp
Brums [2.3K]

Answer:

ghdtgfgrdvreeeegrwwggegteefewqrwefrwerrftrtdsfgyuytfgererdf

Explanation:

The given data is as follows.

     V_{1} = 1.50 L,    T_{1} = 159 K,

      P_{1} = 5.00 atm,   V_{2} = 0.2 L,

       T_{2} = ?,       P_{2} = 50.0 atm  

And, according to ideal gas equation,  

               \frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.          

 \frac{5.0 atm \times 1.50 L}{159 K} = \frac{5 atm \times 0.2 L}{T_{2}}

            T_{2} = 21.27 K

Thus, we can conclude that the final temperature is 21.27 K .

5 0
3 years ago
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