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Naddika [18.5K]
3 years ago
10

Cells grouped together to make a specific part of the body of a plant or animal are called: an organism photosynthesis a tissue

Chemistry
1 answer:
tamaranim1 [39]3 years ago
7 0

Answer:

THE CORRECT ANWER IS ;Cells make up tissues, tissues make up organs, and organs make up organ ... All the systems of the body work together to keep an organism up and running. ... out a particular function, and groups of organs with related functions make up the ... Connective tissue supports and, as the name suggests, connects other tissues.

Explanation:

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What is science......?​
den301095 [7]

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5 0
3 years ago
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What pressure is required to achieve a co2 concentration of 7.90×10−2 m at 20∘c?
Savatey [412]

Answer:-  1.90 atm

Solution:- It is based on combined gas law equation, PV = nRT

In this equation, P is pressure, V is volume, n is moles of gas, R is universal gas constant and T is kelvin temperature.

If we divide both sides by V then:

P=\frac{nRT}{V}

We know that, molarity is moles per liter. So, in the above equation we could replace \frac{n}{V} by molarity, M of the gas. The equation becomes:

P = MRT

T = 20 + 273 = 293 K

M = 7.9*10^-^2

Let's plug in the values in the equation:

P = (7.9*10^-^2)(0.0821)(293)

P = 1.90 atm

So, the pressure of the gas is 1.90 atm.

7 0
3 years ago
Relationships exist between the algae and coral?
S_A_V [24]
No, they do not. It is not true.
6 0
3 years ago
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A 13.1-g sample of CaCl2 is dissolved in 104 g of water, with both substances at 24.7°C. Calculate the final temperature of the
likoan [24]

Answer:

The final temperature of the solution is 44.8 °C

Explanation:

assuming no heat loss to the surroundings, all the heat of solution (due to the dissolving process) is absorbed by the same solution and therefore:

Q dis + Q sol = 0

Using tables , can be found that the heat of solution of CaCl2 at 25°C (≈24.7 °C)  is q dis= -83.3 KJ/mol . And the molecular weight is

M = 1*40 g/mol + 2* 35.45 g/mol = 110.9 g/mol

Q dis = q dis * n  = q dis * m/M =  -83.3 KJ/mol * 13.1 g/110.9 gr/mol = -9.84 KJ

Qdis= -9.84 KJ

Also Qsol = ms * Cs * (T - Ti)

therefore

ms * Cs * (T - Ti) + Qdis = 0

T=  Ti - Qdis * (ms * Cs )^-1   =24.7 °C - (-9.84 KJ/mol)/[(104 g + 13.1 g)* 4.18 J/g°C] *1000 J/KJ

T= 44.8 °C

7 0
3 years ago
Write and balance the chemical equation for the reaction associated with ΔHof of Li3N(s). What is the sum of all of the coeffici
ivann1987 [24]

Explanation:

In this reaction, the reactants are Li and N2. The product is Li3N

So we have;

Li + N2 → Li3N

Upon balancing, we have;

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The sum of the coefficients is 6 + 1 + 2 = 9

5 0
3 years ago
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