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Jlenok [28]
2 years ago
13

What combination would dissolve a solid solute the fastest?

Chemistry
1 answer:
aleksley [76]2 years ago
3 0

Answer:

The rate of dissolving of a solute in a solvent is faster when the solute and solvent are stirred, the solvent is warmer, or the solute consists of smaller particles with more surface area.

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If a compound is separated into separate parts does the substance remain the same substance
MariettaO [177]
No, if H2O is separated into H2 and O, then it is not the same substance

6 0
3 years ago
what type of element can turn into both solid and liquid form depending on the temperature of its surroundings ?​
lorasvet [3.4K]

<em>Answer:</em>

<em>An Atom can turn into both solid and liquid form depending on the temperature of its surroundings </em>

<em>Explanation:</em>

<em>Scientists have discovered a new state of physical matter in which atoms can exist as both solid and liquid simultaneously. Researchers have found, however, that some elements can, when subjected to extreme conditions, take on the properties of both solid and liquid states.</em>

7 0
3 years ago
Read 2 more answers
What is the speed of a cheetah that runs 30 miles in 0.5 hours?<br> a
REY [17]

Answer:

60 mph (miles per hour)

Explanation:

0.5 hours is 1/2 of an hour, so to get the number of miles for a whole hour you multiply the miles ran by 2.

30 times 2 is 60.

6 0
2 years ago
Read 2 more answers
To what volume should 25ml of 15m nitric acid be diluted to prepare a 3m solution
Maurinko [17]

We can use the dilution formula to find the volume of the diluted solution to be prepared

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting the values in the equation

15 M x 25 mL = 3 M x v2

v2 = 125 mL

The 25 mL concentrated solution should be diluted with distilled water upto 125 mL to make a 3 M solution

6 0
3 years ago
Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e
notsponge [240]

<u>Answer:</u> The concentration of Sn^{2+} in the cell is 9.0\times 10^{-3}M

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u>  Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-   E^o_{Zn^{2+}/Zn}=-0.76V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)   E^o_{Sn^{2+}/Sn}=-0.136V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.136-(-0.76)=0.624V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}

where,

E_{cell} = electrode potential of the cell = 0.660 V

E^o_{cell} = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

[Zn^{2+}]=2.5\times 10^{-3}M

[Sn^{2+}] = ?

Putting values in above equation, we get:

0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})

[Sn^{2+}]=9.0\times 10^{-3}M

Hence, the concentration of Sn^{2+} ions is 9.0\times 10^{-3}M

3 0
3 years ago
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