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2 years ago

What is 620,000 rounded to the nearest ten thousand

Mathematics

2 answers:

Degger [83]2 years ago

8 0

The answer is 600,000

hope this helps

Sedaia [141]2 years ago

5 0

620,000 rounded to the nearest thousand is:

620,000 because 2 is less than 5

Hope I Helped You!!!

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Prove that under root 2 is a irrational number

torisob [31]

Answer:

Let's suppose √2 is a rational number. Then we can write it √2 = a/b where a, b are whole numbers, b not zero.

We additionally assume that this a/b is simplified to lowest terms, since that can obviously be done with any fraction. Notice that in order for a/b to be in simplest terms, both of a and b cannot be even. One or both must be odd. Otherwise, we could simplify a/b further.

From the equality √2 = a/b it follows that 2 = a2/b2, or a2 = 2 · b2. So the square of a is an even number since it is two times something.

From this we know that a itself is also an even number. Why? Because it can't be odd; if a itself was odd, then a · a would be odd too. Odd number times odd number is always odd. Check it if you don't believe me!

Okay, if a itself is an even number, then a is 2 times some other whole number. In symbols, a = 2k where k is this other number. We don't need to know what k is; it won't matter. Soon comes the contradiction.

If we substitute a = 2k into the original equation 2 = a2/b2, this is what we get:

2=(2k)2/b22=4k2/b22*b2=4k2b2=2k2

This means that b2 is even, from which follows again that b itself is even. And that is a contradiction!!!

WHY is that a contradiction? Because we started the whole process assuming that a/b was simplified to lowest terms, and now it turns out that a and b both would be even. We ended at a contradiction; thus our original assumption (that √2 is rational) is not correct. Therefore √2 cannot be rational.

(I copied this from the internet, but hope it helps!)

4 0

3 years ago

Read 2 more answers

What is the correct answer?

Tasya [4]

Given:

The function is

$f(x)=(x+3)^2(x-5)^6$

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

$P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}$ ...(i)

where, a is a constant, $c_1,c_2,...,c_n$ are zeros of respective multiplicities $m_1,m_2,...,m_n$ .

We have,

$f(x)=(x+3)^2(x-5)^6$

On comparing this with (i), we get

$c_1=-3,m_1=2$

$c_2=5,m_2=6$

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

5 0

2 years ago

Select the correct answer. Sean and Colleen are raking leaves in their yard. Working together, they can clear the yard of leaves

Lera25 [3.4K]

Answer:

40 minutes

Step-by-step explanation:

Let c represent the number of minutes it would take colleen to finish the job when he is working alone. Hence, it can be represented by the equation:

$\frac{1}{c}+\frac{1}{c+20} =\frac{1}{24} \\\\Finding\ the\ L.C.M\ of\ the\ fraction\ to\ get\ 24c(c+20)\ as\ the\ L.C.M.\\Multiply\ the\ whole\ equation\ by\ 24c(c+20):\\\\\frac{1}{c}(24c(c+20))+\frac{1}{c+20}(24c(c+20)) =\frac{1}{24}(24c(c+20)) \\\\24c+480+24c=c^2+20c\\\\48c+480=c^2+20c\\\\c^2+20c-48c-480=0\\\\c^2-28c-480=0$