<span>2 x^2 y^6 z^5
5 x^4 y^5 z^3
---------------
10 ^6 ^11 ^8</span>
sorry to my answer ineed a point and i ask a question sory and thnks:(
Answer:
The average rate of change

At t = 1

at t=3
Step-by-step explanation:
<u><em>Step(I)</em></u>:-
The given function h(t) = 3+70t - 16t²

The
70 - 32 t = 0
⇒ 70 = 32 t
⇒ 
<em>Step(ii</em>):-
The average rate of change in h(t) between t = 1 second and t = 3 second

At t = 1

At t = 3
Without converting the equations to the same form, the property that must be different in the functions is the slope
<h3>How to determine the difference in the properties of the functions?</h3>
From the question, the equations are given as
y = x + 5
y + x = 5
From the question, we understand that:
The equations must not be converted to the same form before the question is solved
The equation of a linear function is represented as
y = mx + c
Where m represents the slope and c represents the y-intercept
When the equation y = mx + c is compared to y = x + 5, we have
Slope, m = 1
y-intercept, c = 5
The equation y = mx + c can be rewritten as
y - mx = c
When the equation y - mx = c is compared to y + x = 5, we have
Slope, m = -1
y-intercept, c = 5
By comparing the properties of the functions, we have
- The functions have the same y-intercept of 5
- The functions have the different slopes of 1 and -1
Hence, the different properties of the functions are their slopes
Read more about linear functions at
brainly.com/question/15602982
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We begin with an unknown initial investment value, which we will call P. This value is what we are solving for.
The amount in the account on January 1st, 2015 before Carol withdraws $1000 is found by the compound interest formula A = P(1+r/n)^(nt) ; where A is the amount in the account after interest, r is the interest rate, t is time (in years), and n is the number of compounding periods per year.
In this problem, the interest compounds annually, so we can simplify the formula to A = P(1+r)^t. We can plug in our values for r and t. r is equal to .025, because that is equal to 2.5%. t is equal to one, so we can just write A = P(1.025).
We then must withdraw 1000 from this amount, and allow it to gain interest for one more year.
The principle in the account at the beginning of 2015 after the withdrawal is equal to 1.025P - 1000. We can plug this into the compound interest formula again, as well as the amount in the account at the beginning of 2016.
23,517.6 = (1.025P - 1000)(1 + .025)^1
23,517.6 = (1.025P - 1000)(1.025)
Divide both sides by 1.025
22,944 = (1.025P - 1000)
Add 1000 to both sides
23,944 = 1.025P
Divide both by 1.025 for the answer
$22,384.39 = P. We now have the value of the initial investment.