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Rudiy27
3 years ago
15

CAN SOMEONE PLEASE HELP ME WITH THE QUESTION IN THE IMAGE

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Option D:

m ∠2 = 27°, m ∠3 = 90°

Solution:

Given ABCD is a rhombus.

Measure of ∠1 = 27°

<u>To find the measures of ∠2 and ∠3:</u>

By the property of rhombus,

Diagonals bisect the angles.

Therefore, ∠1 = ∠2

Measure of ∠2 = 27°

Again by the property of rhombus,

Diagonals bisect each other at right angles.

Right angle = 90°

Here ∠3 is bisecting angle of the diagonals.

Therefore, measure of ∠3 = 90°.

So, Option D is the correct answer.

Hence m ∠2 = 27°, m ∠3 = 90°.

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3 years ago
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<u>Answer:</u>

The equivalent of -1/3t = 4/3​ is t = -4

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Need to determine such value of t so that when it is multiplied by -1/3, we should get 4/3

That is we need to solve following expression for value of t.

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\begin{array}{l}{-\frac{1}{3} t \times 3=\frac{4}{3} \times 3} \\\\ {=>-t=4}\end{array}

Now multiplying both the sides by -1 we get

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3 years ago
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Answer:

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By pulling out the common factors for each pair of terms, we can rewrite the original polynomial like this:

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