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3 years ago

Compare factoring by grouping to factoring out the greatest common factor.

Mathematics

1 answer:

Blababa [14]3 years ago

7 0

Answer:

(3x + 10)(2x + 1)

Step-by-step explanation:

Factor by grouping: 6x2 + 3x + 20x + 10.

This is a polynomial written with four terms that don't have a single common factor among them. However, the first two terms have a common factor (3x), and the last two terms have a common factor (10). This situation doesn't answer all of our wildest factoring dreams, but we'll take it.

By pulling out the common factors for each pair of terms, we can rewrite the original polynomial like this:

3x(2x + 1) + 10(2x + 1)

These two terms now have a common factor of (2x + 1). Seems like we should be able to do something with that information, don't you think? In fact, we can pull out this common factor and rewrite the polynomial again:(3x + 10)(2x + 1)

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Answer:

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Step-by-step explanation:

Given

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Required

The solution

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Add (1) and (2)

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Rewrite as:

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Multiply both sides by e

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So, we have:

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$y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}$

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