All categories

3 years ago

Please help!!!i don't understand?

Mathematics

1 answer:

ruslelena [56]3 years ago

6 0

Do you understand?? :D

You might be interested in

Please help if you can!

natita [175]

Answer:

it is $\frac{9}{10}$ over $\frac{3}{5}$

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Can someone help me, please?

katovenus [111]

The sign would be negative

X is in the negative area meaning that when x/y and multiplied by y, it would stay negative since y is positive

4 0

3 years ago

Read 2 more answers

I need help with number 2 and three.

wolverine [178]

Answer:

I think it is acute because if the angle was over 90 degrees it would be and obtuse then

Step-by-step explanation: I hope this helps u out very much thank you :)

8 0

3 years ago

Read 2 more answers

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago

2y+3=-2x written in slope intercept form

Alex777 [14]

Y=-x-3/2
That's it written in slope intercept form

3 0

3 years ago