3 years ago

HELP what is the answer to this question?

Physics

1 answer:

Dennis_Churaev [7]3 years ago

7 0

I think it’s c sorry if wrong

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A pitcher delivers a fast ball with a velocity of 43 m/s to the south. the batter hits the ball and gives it a velocity of 51 m/

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Assuming north as positive direction, the initial and final velocities of the ball are:
$v_i=-43 m/s$ (with negative sign since it is due south)
$v_f=+51 m/s$
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$a= \frac{v_f-v_i}{t}= \frac{51 m/s-(-43 m/s)}{0.001 s}=9.4 \cdot 10^4 m/s^2$
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If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave?

GaryK [48]

Answer:

f = 614.28 Hz

Explanation:

Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :

$f=\dfrac{nv}{4l}$

$f=\dfrac{1\times 344}{4\times 0.14}$

f = 614.28 Hz

So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.

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4 years ago

Superman throws a 2400 n boulder at a villain. what horizontal force must superman apply to the boulder to give a horizontal acc

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The boulder has a weight of W=2400 N. The weight of an object is the product between its mass m and the gravitational acceleration g:
$W=mg$
Rearranging the relationship, we can calculate the mass of the boulder:
$m= \frac{W}{g}= \frac{2400 N}{9.81 m/s^2}=244.6 kg$

We are told that Superman applies a horizontal force to this object, and as a result, the acceleration of the boulder is $a=12.0 m/s^2$ . We can find the force applied by using Netwon's second law of motion:
$F=ma=(244.6 kg)(12.0 m/s^2)=2935 N$

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3 years ago