A 3.5 kg block slides along a frictionless horizontal with a speed of 2.5 m/s. After sliding a distance of 5 m, the block makes
1 answer:
Answer:
L = 0.416 m
Explanation:
In this exercise to calculate the distance traveled in the branch that climbs the block we can use the concepts of energy
Starting point Flat part
Em₀ = K = ½ m v²
Final point. Highest part of the ramp
= U = m g h
As there is no friction the mechanical energy is conserved
Em₀ =
½ m v² = m g h
h = v² / 2g
h = 2.5 2/2 9.8
h = 0.3189 m
The distance traveled can be found with trigonometry
sin 50 = h / L
L = h / sin 50
L = 0.3189 / sin50
L = 0.416 m
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Answer:
8.4 V
Explanation:
induced emf, e1 = 5.8 V
Magnetic field, B1 = 0.38 T
magnetic field, B2 = 0.55 T
induced emf, e2 = ?
As we know that the induced emf is directly proportional to the magnetic field strength.
When the other parameters remains constant then
e2 = 8.4 V
Thus, the induced emf is 8.4 V.
Answer:
2805 °C
Explanation:
If the gas in the tank behaves as ideal gas at the start and end of the process. We can use the following equation:
The key issue is identify the quantities (P,T, V, n) in the initial and final state, particularly the quantities that change.
In the initial situation the gas have an initial volume , temperature
, and pressure
,.
And in the final situation the gas have different volume and temeperature
, the same pressure
,, and the same number of moles
,.
We can write the gas ideal equation for each state:
and
, as the pressure are equals in both states we can write
solving for
(*)
We know = 935 °C, and that the
(the complete volume of the tank) is the initial volume
plus the part initially without gas which has a volume twice the size of the initial volume (read in the statement: the other side has a volume twice the size of the part containing the gas). So the final volume
Replacing in (*)