A 3.5 kg block slides along a frictionless horizontal with a speed of 2.5 m/s. After sliding a distance of 5 m, the block makes
1 answer:
Answer:
L = 0.416 m
Explanation:
In this exercise to calculate the distance traveled in the branch that climbs the block we can use the concepts of energy
Starting point Flat part
Em₀ = K = ½ m v²
Final point. Highest part of the ramp
= U = m g h
As there is no friction the mechanical energy is conserved
Em₀ =
½ m v² = m g h
h = v² / 2g
h = 2.5 2/2 9.8
h = 0.3189 m
The distance traveled can be found with trigonometry
sin 50 = h / L
L = h / sin 50
L = 0.3189 / sin50
L = 0.416 m
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The kinetic energy of the cart is 24 J.
<u>Explanation:</u>
The acceleration of a given mass from rest to the velocity is known as kinetic energy. It gains energy from acceleration and remains in this state until the speed of the object changes.
The kinetic energy is the given by,
K.E = 1/2 mv^2
Given the mass m = 3 kg, v = 4 m / s.
K.E = 1/2 3
(4)^2
K.E = 24 J.
Answer:
Explanation:I don't say you have to mark my ans as brainliest but if you think it has really helped you plz don't forget to thank me ...
