A 3.5 kg block slides along a frictionless horizontal with a speed of 2.5 m/s. After sliding a distance of 5 m, the block makes
1 answer:
Answer:
L = 0.416 m
Explanation:
In this exercise to calculate the distance traveled in the branch that climbs the block we can use the concepts of energy
Starting point Flat part
Em₀ = K = ½ m v²
Final point. Highest part of the ramp
= U = m g h
As there is no friction the mechanical energy is conserved
Em₀ =
½ m v² = m g h
h = v² / 2g
h = 2.5 2/2 9.8
h = 0.3189 m
The distance traveled can be found with trigonometry
sin 50 = h / L
L = h / sin 50
L = 0.3189 / sin50
L = 0.416 m
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Explanation:
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Answer:
Fr = 48 [N] forward.
Explanation:
Suppose the movement is on the X axis, in this way we have the force of the engine that produces the movement to the right, while the force produced by the brake causes the vehicle to decrease its speed in this way the sign must be negative.
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