A 3.5 kg block slides along a frictionless horizontal with a speed of 2.5 m/s. After sliding a distance of 5 m, the block makes
1 answer:
Answer:
L = 0.416 m
Explanation:
In this exercise to calculate the distance traveled in the branch that climbs the block we can use the concepts of energy
Starting point Flat part
Em₀ = K = ½ m v²
Final point. Highest part of the ramp
= U = m g h
As there is no friction the mechanical energy is conserved
Em₀ =
½ m v² = m g h
h = v² / 2g
h = 2.5 2/2 9.8
h = 0.3189 m
The distance traveled can be found with trigonometry
sin 50 = h / L
L = h / sin 50
L = 0.3189 / sin50
L = 0.416 m
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Answer:
Initial speed of the spaceship 1, v = 2 m/s
Explanation:
Given that :
Mass of spaceship 1 and 2 that have equal mass are 300 kg
Initial momentum of the spaceship 1 is 600 kg-m/s
To find :
We need to find the initial momentum of spaceship 1.
Solve :
The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :
v = 2 m/s
Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.