It would be A: Have a greater height.
The higher the wave the higher the energy!
Answer:
μ = tanθ = tan30 = 0.58
Explanation:
μ = force parallel/force perpendicular = mgsinθ/mgcosθ = tanθ
The AU ... Astronomical Unit ... used to be defined as the average distance between the Sun and Earth during the year.
Now it's defined as 149,597,870,700 meters exactly.
The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.
<h3>What is electrical power?</h3>
Electrical power is the rate at which electrical work is done.
- Electrical power = voltage × current
The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.
Total power dissipated = 5 × 2.5 = 12.5 Watts
- Work done = power × time (in seconds)
Work done = 12.5 × (1 × 3600 + 15 × 60)
Work done = 56250 J = 56.25 kJ
Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.
Learn more about electrical power and work done at: brainly.com/question/23901751
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Answer:
(a) Distance traveled = 75.3846 m
(b) Velocity of car at that instant will be 14 m/sec
Explanation:
We have given acceleration of the car 
Initial velocity of the cart u = 0 m/sec
(a) According to second equation of motion we know that 
So distance traveled by car 
As the truck is moving with constant speed
So distance traveled by truck 
As the truck overtakes the car
So 


So distance traveled 
(b) From second equation of motion we know that v = u+at
So v = 0+1.3×10.769 = 14 m /sec