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schepotkina [342]
3 years ago
5

Squaring a number and then multiplying the result by 4 what is that number

Mathematics
1 answer:
kogti [31]3 years ago
6 0

Answer:

c*4, but I don't think this is what you are looking for. I need numbers to help better.

Step-by-step explanation:

n=number

n^2=c

c*4

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PLEASEEEE HELP I NEED A ANSWER ASAP!!!!!!!
Licemer1 [7]

Answer:

520 - 303.93 - (10.99 * 4) - 25.25 - 73.43x ≥ 0

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1) Parentheses

520 - 303.93 - 43.96 - 25.25 - 73.43x ≥ 0

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2) Combine like terms

146.86 - 73.43x ≥ 0

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3) Get the variable term alone

-73.43x ≥ -146.86

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4) Divide to solve

x ≤ 2

** dividing by a negative number, the inequality sign flips **

ANSWER :

x ≤ 2

8 0
2 years ago
Read 2 more answers
Write a number of your choice, using the following clues:
guapka [62]

Answer:

90

Step-by-step explanation:

90÷2= 45

90÷3=30

8 0
3 years ago
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Help me with geometry plzzzzzzzzzzzzzzzzzzzz
Natalija [7]

Answer:

x = 17

Step-by-step explanation:

A triangle's sum is 180 degrees, hence

6x + 10 + x + 17 + 4x - 34 = 180.

11x + 10 + 17 - 34 = 180

11x - 7 = 180

11x = 187

x = 17

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3 0
3 years ago
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15 feet long and 12 feet wide. What is its area in square yards?
deff fn [24]
180 is the answer . Just multiply both numbers.
7 0
3 years ago
Assume, for the sake of this question, that the data were collected through a well-designed, well-implemented random sampling me
amid [387]

Answer:

Since the pvalue of the test is 0.2743 > 0.1, the threshold probably was met.

Step-by-step explanation:

The widget manufacturing company had established a threshold of 60% preferring the proposed new widget to move forward with producing the new widgets.

This means that at the null hypothesis we test if the proportion is at least 60%, that is:

H_{0}: p \geq 0.6

And the alternate hypothesis is:

H_{a}: p < 0.6

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that:

\mu = 0.6

\sigma = \sqrt{0.6*0.4}

Three hundred thirty-eight of 575 respondents reported preferring the proposed new widget.

This means that n = 575, X = \frac{338}{575} = 0.5878

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.5878 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{575}}}

z = -0.6

Pvalue of the test and decision:

We want to find the probability of a proportion of 0.5878 or lower, which is the pvalue of z = -0.6.

Looking at the z-table, z = -0.6 has a pvalue of 0.2743.

Since 0.2743 > 0.1, the threshold probably was met.

3 0
3 years ago
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