Answer: 5 benches and 23 students
Step-by-step explanation:
I will answer in English.
We have E students and B benches.
If we sit 4 students per bench, we have 3 students left.
then:
E = 4*B + 3
And if we sit 5 students per bench, there are two places with no students sited.
E = 5*B - 2
now we can replace the E in the second equation with the right part in the first equation:
4*B + 3 = 5*B - 2
3 + 2 = 5*B - 4*B
5 = B
So we have 5 benches, and:
E = 4*5 + 3 = 23 students.
Answer:
Answer in simplified mixed form is 1 5/6
Step-by-step explanation:
We need to solve: -6 7/8 divided by (-3 3/4)
This can be written as:
-6 7/8 ÷ (-3 3/4)
Since -6 7/8 = -55/8 and -3 3/4 = - 15/4
So we can write :
-6 7/8 ÷ (-3 3/4) = -55/8 ÷ (-15/4)
or (-55/8 ) / (-15/4)
or (-55/8) * (-4/15)
or -(-220/120)
or 11/6
or 1 5/6 , this is the answer
We got the answer in simplified mixed form is 1 5/6
5y - 2x + 1 = 0.
5y = 2x-1.
y = 2/5 x - 2/5
this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)
tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2
Answer:
x=2
y=-5
Step-by-step explanation:
-3(4y+22)-y=-1
-12y-66-y=-1
-13y-66=-1
-13y=65
y=-5
x=4(-5)+22
x=-20+22
x=2
