All categories

3 years ago

Write the equation if the line that passes through the point (3,5)

2 answers:

8 0

Since the line is parallel to the graph y = 2/3x + 1, then it must have a gradient of 2/3, by definition.

Hence, let's use the point-gradient form:
$y - y_1 = \frac{2}{3}(x - x_1)$ , where (x₁, y₁) are the coordinates we're passing through

$y - 3 = \frac{2}{3}(x - 5)$
$3y - 9 = 2x - 10$
$3y = 2x - 1$
$y = \frac{2}{3}x + 3$

Bingel [31]3 years ago

3 0

Not enough information to solve

You might be interested in

What is 7 divided by 43,786

Ksenya-84 [330]

Answer:

6,255.1428571429

Step-by-step explanation:

This is a irrational number btw

6 0

2 years ago

How would you explain surface area and volume to a 6th grader who is just now learning about these concepts?

AnnyKZ [126]

Answer: Surface area is the sum of the areas of all faces (or surfaces) on a 3D shape. A cuboid has 6 rectangular faces. To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area. you should explain with a net its easier.

Step-by-step explanation:

hope this helps and sorry bout the smack comment lol

6 0

2 years ago

Keiko determined that the coordinate points (–4, 0), (–3, –1), and (2, –6) are solutions to the following system. y = − x − 4 y

Bess [88]

Answer:

only (-4,0) is a reasonable solution.

Step-by-step explanation:

In order to see which ones are reasonable we need to apply the points to the system and check if they make both equations valid at the same time.

y = -x - 4

y = x² + x - 12

For (-4, 0):

0 = -(-4) - 4 -> 0 = 4 -4 -> 0 = 0 (valid)

0 = (-4)² - 4 - 12 -> 0 = 16 - 16 -> 0 = 0 (valid)

For (-3, -1):

-1 = -(-3) -4 -> -1 = 3 -4 -> -1 = -1 (valid)

-1 = (-3)² -1 - 12 -> -1 = 9 -13 -> -1 = -4 (invalid)

For (2, -6):

2 = -(-6) - 4 -> 2 = 6 -4 -> 2 = 2 (valid)

2 = (-6)² -6 -12 -> 2 = 36 -18 -> 2 = 18 (invalid)

Therefore only (-4,0) is a reasonable solution.

7 0

3 years ago

Renaldo catches the bus at 4:00 pm to ride 3.2 miles from his house to the dentists office. he arrives at 4:30 pm, for a one hou

andrew11 [14]

Answer:

Step-by-step explanation:

speed = distance/time

so renaldo speed = 3.2/0.5 = 6.4miles/hr (since time taken is 1/2 hr)

now after 1 hr of his appoinment i.e at 5:30pm he took bus whose speed is same as before i.e 6.4 miles/hr

now time taken to cover this 4.8 miles = 4.8/6.4 = 3/4 hr (since time = distance /speed )

3/4 hr = 3/4 * 60 = 45 minutes

so he reached at 6:15pm . so he will be on time.

8 0

3 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

3 years ago