There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
Answer:
- The diagram bar is attached.
- Addition equation: 
- Multiplication equation: 
- How are the equation related? Each equation shows 3 groups of 7.
Step-by-step explanation:
We know that Jan buys 3 bags of beads and each bag contains 7 beads, then, you can draw the bar diagram shown attached.
Observe that the diagram has 3 blocks (each block represents a bag of bead) and there is a number 7 inside of each block (which is the number of beads contained in a bag).
Therefore:
- Add the numbers inside the blocks in order to get the addition equation that shows the number of beads Jan buys. This is:
- Multiply 3 blocks by 7 in order to get multiplication equation that show the number of beads Jan buys:
The equations are related. Each one shows 3 groups of 7.
<em> </em><em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>7</em><em>5</em><em>.</em><em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>
The measure represents the standard deviation of the sample means and is used in place of the population standard deviation when the population parameters are unknown is; t-test.
<h3>Which measure is used when the population parameters are unknown?</h3>
A hypothesis test for a population mean when In the case that the population standard deviation, σ, is unknown, carrying out a hypothesis test for the population mean is done in similarly like the population standard deviation is known. A major distinctive property is that unlike the standard normal distribution, the t-test is invoked.
Read more on t-test;
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I hope this helps!
25 is 7.8
26 is 8.3
27 is 14.5
28 is yes, they both ran the same distance because 7×5 is equal to 5×7. They both equal 35. So, both ran the same distance.
