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Fed [463]
2 years ago
14

Which measure represents the standard deviation of the sample means and is used in place of the population standard deviation wh

en
the population parameters are unknown?
Mathematics
1 answer:
Ksivusya [100]2 years ago
4 0

The measure represents the standard deviation of the sample means and is used in place of the population standard deviation when the population parameters are unknown is; t-test.

<h3>Which measure is used when the population parameters are unknown?</h3>

A hypothesis test for a population mean when In the case that the population standard deviation, σ, is unknown, carrying out a hypothesis test for the population mean is done in similarly like the population standard deviation is known. A major distinctive property is that unlike the standard normal distribution, the t-test is invoked.

Read more on t-test;

brainly.com/question/6501190

#SPJ1

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Answer:

x^6+x^4+4x^3-2x^2-x+3

Step-by-step explanation:

x^3+2x+3

\times(x^3-x+1)

---------------------------------

First step multiply your terms in your first expression just to the 1 in the second expression like so:

x^3+2x+3

\times(x^3-x+1)

---------------------------------

x^3+2x+3  Anything times 1 is that anything.

That is, (x^3+2x+3) \cdot 1=x^3+2x+3.

Now we are going to take the top expression and multiply it to the -x in the second expression. -x(x^3+2x+3)=-x^4-2x^2-3x.  We are going to put this product right under our previous product.

x^3+2x+3

\times(x^3-x+1)

---------------------------------

x^3+2x+3

-x^4-2x^2-3x  

We still have one more multiplication but before we do that I'm going to put some 0 place holders in and get my like terms lined up for the later addition:

x^3+2x+3

\times(x^3-x+1)

---------------------------------

0x^4+x^3+0x^2+2x+3

-x^4+0x^3-2x^2-3x+0  

Now for the last multiplication, we are going to take the top expression and multiply it to x^3 giving us x^3(x^3+2x+3)=x^6+2x^4+3x^3. (I'm going to put this product underneath our other 2 products):

x^3+2x+3

\times(x^3-x+1)

---------------------------------

0x^4+x^3+0x^2+2x+3

-x^4+0x^3-2x^2-3x+0  

x^6+2x^4+3x^3

I'm going to again insert some zero placeholders to help me line up my like terms for the addition.

x^3+2x+3

\times(x^3-x+1)

---------------------------------

0x^6+0x^4+x^3+0x^2+2x+3

0x^6-x^4+0x^3-2x^2-3x+0  

x^6+2x^4+3x^3+0x^2+0x+0

----------------------------------------------------Adding the three products!

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Answer:

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