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3 years ago

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A rectangle has an area of 72 in². The length and the width of the rectangle are changed by a scale factor of 3.5.

1 answer:

Ira Lisetskai [31]3 years ago

3 0

For this problem, it can be solved by forming two equations. The first equation is the area of the original rectangle. Let l be the length and w be the width. l x w = 72 will be 1st equation. Then, the 2nd equation is 3.5l * 3.5w = A. By substitution, the new area, A = 12.25( l x w) = 12.25 (72) = 882 in<span>².</span>

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2. Find the measure of angle L.

BabaBlast [244]

Answer:

∠ L ≈ 21.6°

Step-by-step explanation:

Using the Sine rule in the triangle

$\frac{MN}{sinL}$ = $\frac{LM}{sinN}$ , that is

$\frac{34}{sinL}$ = $\frac{42}{sin27}$ ( cross- multiply )

42 × sinL = 34 × sin27° ( divide both sides by 42 )

sinL = $\frac{34sin27}{42}$ , then

∠ L = $sin^{-1}$ ( $\frac{34sin27}{42}$ ) ≈ 21.6° ( to the nearest tenth )

4 0

2 years ago

Plllzzzzzzz Heeeeeelllpppppppppppp!!!!

e-lub [12.9K]

On the first place we need to write the value of x, on the second place - the value of y.
{(-3,3), (0,0), (2,-2)}.

So, the answer is A.

4 0

2 years ago

Use the properties of exponents to simplify the expression: 212 × 232

Tanzania [10]

Answer:

Man's in Ce

Step-by-step explanation:

8 0

2 years ago

Raylin went to the park with her friends and found a soccer ball. She picked up the soccer ball and kicked it as high as she cou

Tems11 [23]

Answer:

The maximum height is: $h(t_{max})=14.39 \: u$

The ball reaches the ground in 1.79 s.

Step-by-step explanation:

We need to take the derivative and equal to zero to find the time at the maximum height.

$h(t)=-16t^{2} +27t+3$ (1)

$\frac{dh(t)}{dt}=-32t +27=0$

$t_{max} =\frac{27}{32}$

$t_{max} =0.84\: u$

Now, we just need to put t(max) into equation (1) to find h(max)

$h(t_{max})=-16(0.84)^{2} +27(0.84)+3$

$h(t_{max})=-16(0.84)^{2} +27(0.84)+3$

$h(t_{max})=14.39 \u$

If we want to get the time when the ball reaches the ground we just need to equal h(t) to zero.

$0=-16t^{2} +27t+3$

Let's solve this quadratic equation.

We will get two solutions and we must choose the positive value.

t1 = 1.79 u

t2 = -0.10 u

Therefore, the ball reaches the ground in 1.79 u.

I hope it helps you!

7 0

3 years ago

Please help.<br><br> BD bisects

Maslowich

<h3>Answer: angle EBD = 50 degrees</h3>

======================================================

Explanation:

BD bisects angle EBC

This means the angle EBC is broken up into two smaller equal pieces angle EBD and angle DBC

So,

angle DBC = angle EBD

7x+8 = 5x+20

7x-5x = 20-8

2x = 12

x = 12/2

x = 6

Now that we know x, we can find each angle

angle DBC = 7x+8

angle DBC = 7*6+8

angle DBC = 42+8

angle DBC = 50 degrees

and

angle EBD = 5x+20

angle EBD = 5*6+20

angle EBD = 30+20

angle EBD = 50 degrees

Both angles are 50 degrees, to this confirms our answer.

8 0

2 years ago