Answer:
The test statistic is t = 3.36.
Step-by-step explanation:
You're testing the claim that the mean difference is greater than 0.7.
At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.
0.7 is tested at the null hypothesis:
This means that 
A survey of 35 people was conducted to compare their self-reported height to their actual height.
This means that 
From the sample, the mean difference was 0.95, with a standard deviation of 0.44.
This means that 
Calculate the test statistic



The test statistic is t = 3.36.