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4 years ago

A rectangle has an area of 72 in². The length and the width of the rectangle are changed by a scale factor of 3.5.

1 answer:

3 0

For this problem, it can be solved by forming two equations. The first equation is the area of the original rectangle. Let l be the length and w be the width. l x w = 72 will be 1st equation. Then, the 2nd equation is 3.5l * 3.5w = A. By substitution, the new area, A = 12.25( l x w) = 12.25 (72) = 882 in<span>².</span>

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Evaluate a+b for a =34 and b=-6

Digiron [165]

Question

evaluate a+b for a =34 and b=-6

a + b =

34 + (-6) =

34 - 6 =

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3 years ago

Read 2 more answers

Expand and Simplify 3(4x + 1 ) -2(3x-4)

pychu [463]

Answer:

<h3> $\boxed{ \bold{ 6x + 11}}$ </h3>

Step-by-step explanation:

$\mathsf{3(4x + 1) - 2(3x - 4)}$

Distribute 3 through the parentheses

$\mathsf{12x + 3 -2(3x - 4)}$

Distribute 2 through the parentheses

⇒ $\mathsf{12x + 3 - 6x + 8}$

Collect like terms

⇒ $\mathsf{6x + 11}$

Hope I helped!

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4 years ago

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If a particular set of data is approximately normally distributed, we would find that approximately A) 2 of every 3 observations

Kryger [21]

Answer:

A) No

B) No

C) Yes

Step-by-step explanation:

A) 2 out of three observations is equal to

2/3 = 0.67 or 67 %

We know tha the interval

[μ - σ/2 , μ + σ/2] is approximately 68.3 % of the values

Therefore 2 out of 3 would not fall in that interval

4 out of 5 is 4/5 = 0,8 or 80 % If we examine the interval

[μ - σ , μ + σ ] which is approximately 95. Then value 4/5 ( 0,8)

Therefore 0,8 is out of the interval

C) 19/20 = 0,95 or 95 % is almost exact the value for the interval

[μ - 1.5σ , μ + 1.5σ ] That value is inside μ - 2σ , μ + 2

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3 years ago

35,x,and (x+15) what is the equation

Serjik [45]

Answer:

what???!!!! I don't understand! you can writen again

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3 years ago

A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medica

expeople1 [14]

Answer:

The sample mean is of 1925 calories.

The margin of error is of 75 calories.

The sample standard deviation is of 109.7992 calories.

Step-by-step explanation:

Sample mean:

The sample mean is the mean value of the two bounds of the confidence interval. So

$M = \frac{1850 + 2000}{2} = 1925$

The sample mean is of 1925 calories.

The margin of error

Difference between the bounds and the sample mean. So

2000 - 1925 = 1925 - 1850 = 75 calories.

The margin of error is of 75 calories.

Sample standard deviation:

Here, I am going to expand on the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 18 - 1 = 17

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 17 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.898