How do i solve (−7z 4 )(7z)

Mathematics

1 answer:

Natasha2012 [34]3 years ago

4 0

Answer:

-49z^5

Step-by-step explanation:

(−7z^ 4 )(7z)

Multiply the numbers together

-7*7 = -49

Add the exponents

z^4 * z = z^4 * z^1 = z^(4+1) = z^5

Put back together

-49z^5

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Which of the following graphs represents the function f(x) = x4 - 2x3 - 3x2 + 4x + 1?

s2008m [1.1K]

Answer: Graph D will be correct graph for the given function.

Explanation:

Given function $f(x) = x^4-2x^3-3x^2+4x+1$

Since it is a bi-quadratic equation thus it must have 4 roots and (0,1) is one of its point.

Moreover, the degree of the function is even thus the end behavior of the function is $f(x)\to+\infty$ , as $x\to-\infty$ and $f(x)\to+\infty$ as $x\to+\infty$

In graph A, function has four root but it does not have the end behavior same as function f(x).( because in this graph $f(x)\to-\infty$ , as $x\to-\infty$ and $f(x)\to-\infty$ , as $x\to+\infty$ .) so, it can not be the graph of given function.

In graph B, neither it has four root nor it has the end behavior same as function f(x).(because in this graph $f(x)\to+\infty$ as $x\to-\infty$ and $f(x)\to-\infty$ as $x\to+\infty$ .) so, it can not be the graph of given function.

In graph C, neither it has four root nor it has the same end behavior as function f(x).(because in this graph $f(x)\to-\infty$ as $x\to-\infty$ and $f(x)\to+\infty$ as $x\to\infty$ .) so, it also can not be the graph of given function.