Use the binomial theorem:

The <em>x</em> ³ terms occurs for 5 - <em>k</em> = 3, or <em>k</em> = 2, and its coefficient would be

Answer:
okay not clear,
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Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
b/c the function goes thur the point (1,4) we know it's 4 times more than f(x) so g(x) = 4
Step-by-step explanation:
plug y value :
10=1/2x+8
1/2x=2
x=4