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tangare [24]
3 years ago
10

Identify the height of the rectangle, given that A=(24x2+96x) ft2.

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

Second option, h=(x^{2} + 4x) ft

Step-by-step explanation:

Area = Base x Height

Height = Area ÷ Base

= \frac{24x^{2} +96x}{24}

= \frac{24x^{2} }{24} +\frac{96x}{24} (split fraction for easier simplification)

= x^{2} +4x

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Step-by-step explanation:

The equations will yield the volume of a triangular prism is V = Bh.

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5 0
2 years ago
I don't know what to do
True [87]
Your answer is 1/4, -7/3,-4
8 0
3 years ago
Prove the quotient rule. hint: you can do this directly, but it may be easier to find the derivative of 1/x and then use the cha
Bess [88]
The quotient rule is
d(u/v) = (u dv - v du) / u2

d(u/v) can written as
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5 0
3 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
2 years ago
PLEASE HELP ME ASAP!!
Dmitry_Shevchenko [17]
13 cm+ 13 cm= 26 cm, 26 cm is the answer to Part B.
3 0
3 years ago
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