$v=2\ m/s\\\\E_k=16\ J=16\ \frac{kgm^2}{s^2}\\\\E_k=\frac{mv^2}{2}\\\\\frac{m\cdot(2\ m/s)^2}{2}=16\ \frac{kgm^2}{s^2}\\\\\frac{m\cdot4\ m^2/s^2}{2}=16\ \frac{kgm^2}{s^2}\\\\2m\ m^2/s^2=16\ \frac{kgm^2}{s^2}\ \ /:2\ m^2/s^2\\\\m=8\ kg-answer$

6 0

3 years ago

6<br> 19<br> 97°<br> Х<br> Solve for x on the following triangle

DENIUS [597]

189 gfghhhgghhhhhhbb

3 0

2 years ago

Which table shows a proportional relationship between x and y?

oksano4ka [1.4K]

The top one. Think about the difference between each one: X goes from 1 to 2 and Y goes from 5 to 10. Each number you go up, Y increases by 5. This means there is a proportional relationship.

6 0

2 years ago

Read 2 more answers

A student claims that x=3 and 2+3i are the zeros of a quadratic function. Explain why this is incorrect

Mandarinka [93]

Answer:

Because it's not a quadratic function.

Step-by-step explanation:

8 0

3 years ago