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2 years ago

Can anybody help me pleasee I don't understandd

1 answer:

4 0

Hello there.

6(8 - 2y) = 4y

To solve for this, we need to apply the Distributive Property to the left side of the equation. This property allows us to multiply the number outside of the parenthesis by all numbers inside of the parenthesis.

6(8 - 2y)
6(8) + 6(-2y)
48 - 12y

Now, let’s take a look at our equation.

-12y + 48 = 4y

To make things more simple, we’ll add 12y to both sides of the equation. This will cancel out -12y on the left side of the equation and will turn 4y on the right side of the equation into 16y.

Our new equation is:

16y = 48

Now all we need to do is divide both sides by 16 to solve for y.

16y / 16 = y
48 / 16 = 3

Our final answer and solution is:

Y = 3

I hope this helps!

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For a circle with a radius of 6 feet, what is the measurement of the central angle (in degrees) that intercepts an arc with a le

sp2606 [1]

<h3>The measurement of the central angle is 135 degrees</h3>

<em><u>Solution:</u></em>

<em><u>The length of arc when angle given in degrees is given as:</u></em>

$Arc\ length = \frac{ \theta }{360} \times 2 \pi r$

Where,

r is the radius

$\theta$ is the central angle in degrees

From given,

$r = 6\ feet\\\\Arc\ length = \frac{ 9 \pi }{2}\ feet$

Substituting the values we get,

$\frac{9 \pi }{2} = \frac{ \theta }{ 360} \times 2 \times \pi \times 6\\\\9 \times 360= \theta \times 24\\\\\theta = 135$

Thus the measurement of the central angle is 135 degrees

4 0

2 years ago

The vertices of square RSTV have coordinates R(-1,5), S(-3,1), T(-7,3), and V(-5,7). What is the perimeter of RSTV?

kompoz [17]

The perimeter of square RSTV is: 17.88 units

Further explanation:

As the given figure is a square, all of its sides will be equal. So we have to find one side to find the perimeter.

Given

R(-1,5), S(-3,1), T(-7,3), and V(-5,7)

The distance formula will be used to find the side

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^@}$

Let x be one side of square

$RS=x=\sqrt{(-3-(-1))^2+(1-5)^2}\\=\sqrt{-3+1)^2+(-4)^2}\\=\sqrt(-2)^2+(-4)^2}\\=\sqrt{4+16}\\=\sqrt{20}\\=4.47$

Let P be the perimeter of square

P= 4x

P=4*4.47

=17.88 units

The perimeter of square RSTV is: 17.88 units

Keywords: Perimeter, Distance Formula

Learn more about perimeter at:

#LearnwithBrainly

6 0

2 years ago

Anyone know the answer to to this algebra question?

liraira [26]

Answer:

a=1

b= 1/16

c= 1/256

d= 1

e= 4/9

f= 16/81

Step-by-step explanation:

Plug in the values of X on the left side of the table into the function on the right side of the table. Remember that negative exponents mean the number is under a fraction. 4^-0 is like saying one over 4^0.

For the blue table, because the numbers are already in a fraction and in parentheses, you apply the exponent to each number individually.

7 0

2 years ago

A large serving of soup from a take-out restaurant is 4/5 liter. The restaurant has 3 liters of soup. The diagram below models t

Airida [17]

Answer:

The quantity of total serving soup does restaurant has = T = 2 $\dfrac{2}{5}$ liters .

Step-by-step explanation:

Given as :

The quantity of large serving soup = $\dfrac{4}{5}$ liters

The total quantity of soup does restaurant has = 3 liters

Let the quantity of total serving soup does restaurant has = T liters

So, According to question

The quantity of total serving soup does restaurant has = The quantity of large serving soup × total quantity of soup does restaurant has

Or, T = $\dfrac{4}{5}$ × 3

Or, T = $\frac{4\times 3}{5}$

Or, T = $\dfrac{12}{5}$

∴ T = 2 $\dfrac{2}{5}$ liters

So, quantity of total serving soup does restaurant has = T = 2 $\dfrac{2}{5}$ liters

Hence,The quantity of total serving soup does restaurant has = T = 2 $\dfrac{2}{5}$ liters . Answer

5 0

2 years ago

Which values from the given replacement set make up the solution set of the inequality? 2b≥6;

Bingel [31]

The answer is A because the variable can’t be no lower than 3 and every other answer has 2 in it. 2•(3) is equal to 6 and 2•(4) is greater than 6 which correlates with the sign (greater than or equal to).

5 0

2 years ago