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NARA [144]
3 years ago
14

6 please thank you so much yesss

Mathematics
1 answer:
Lilit [14]3 years ago
5 0
The answer is C..................
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Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

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∴Given Δ ABC is not a right-angle triangle

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c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

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45  = 45+144

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3 years ago
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Explanation:

-3x + 6 = 2x -24

6 + 24 = 2x + 3x

30 = 5x

x = 30/5 = 6

6 0
3 years ago
Read 2 more answers
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