part of the whole painting is gold colored.
<u>Solution:</u>
Given that , In art class, Arthur has created a triangle painting of his painting is purple.
He decided he wants to Paint of the purple area gold
We have to find what fraction of the whole painting will be painting?
Now, part of whole painting is purple
And, part of the purple area is gold ⇒ part of the part of whole painting is gold
Hence, part of the whole painting is gold colored.
<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use
we know that
In the triangle ABC
Applying the law of sines
in this problem we have
therefore
<u>the answer Part 1) is</u>
Law of Sines
<u>Part 2) </u>To find the length of side HI in ∆HIG, use
we know that
In the triangle HIG
Applying the law of cosines
In this problem we have
g=HI
G=angle Beta
substitute
therefore
<u>the answer Part 2) is</u>
Law of Cosines
Step-by-step explanation:
the total surface area is the sum of the individual areas.
we have the ground area : a 6×6 square. = 36 cm²
and we have 4 equal triangles.
the area of a triangle is baseline × height / 2.
which is for each of these triangles
6 × 12 / 2 = 3 × 12 = 36 cm²
so, the total surface area of the pyramid is
36 + 4×36 = 5×36 = 180 cm²
Answer:
The area of the park is 119,966.14 cm if needed to round it would be 119,966 cm.
Step-by-step explanation:
first we would use A=length x width
so a = 614 cm x 212 cm = 130,168 cm
now we find the area of the pond using a= pi x r^2
the diameter is 114 cm so we cut that in half to find the radius which is 57 cm
a = pi x 57^2
a= 3.14 x 3249
a= 10201.86 cm
now we subtract the area of the pond from the whole area
130,168 - 10201.86 = 119,966.14 cm
The area of the park is 119,966.14 cm if needed to round it would be 119,966 cm
Answer:
I think the answer is Step 2, 12x − 16 = 16 + 4x
plz mark me as brainliest if i was right :)