The more reasonable measurement of the distance between the tracks on a CD is 1.6 ⋅ 10^-3 mm. This is also equal to 0.0016mm. <span>1.6 ⋅ 10^3 mm is too large for a CD track</span>
Answer:

Step-by-step explanation:
We can try and isolate m on one side of the equation by following the rules of simplifying equations.

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Answer:
7.
Step-by-step explanation:
-10 /(3 + 2) + 9
= -10 /5 + 9
= -2 + 9
= 7.
Answer:
It is a metaphor.
Step-by-step explanation:
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