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horsena [70]
3 years ago
8

You drive 351.6 miles using 16.4 gallons of gasoline. At this rate, how many gallons of gasoline would you need to drive 1000 mi

les? Round your answer to the tenth place (one place after the decimal).
Mathematics
1 answer:
liberstina [14]3 years ago
3 0

Answer:

46.6 gallons

Step-by-step explanation:

351.6 miles = 16.4 gallons

1000 miles = x gallons

simply cross multiply

351.6 × x = 1000× 16.4 gallons

351.6x = 16400 gallons

x = 16400÷ 351.6

x= 46.643913538

x = 46.6 gallons (rounded to the tenth place)

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Part 2. Laws of sines. Please show work​. Round answer to the nearest tenth.
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Answer:

5) 30.0m

6) 34.0mi

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(all rounded off to the nearest tenth)

Step-by-step explanation:

Please see attached pictures for the full solution.

6 0
3 years ago
What is the equations of the line passing through points (-3,7) and (9,-1)?
diamong [38]

Answer:


y = -2/3x + 5 or A.

8 0
3 years ago
5(3m+2)<br> 6(g+h)<br> 4d+8<br> 21p+35q<br> 18x+9y
aalyn [17]
<span>(a) 5(3m+2) = 15m + 10

(b) 6(g+h) = 6g + 6h

(c) 4d+8 = 4(d + 2)

(d) 21p+35q = 7(3p + 5q)

(e) 18x+9y = 9(2x + y)</span>
7 0
3 years ago
Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3
chubhunter [2.5K]

Answer:

The simplified form is \dfrac{2(x-1)}{3(x+1)}.

x =1 is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

\dfrac{2a^2-4a+2}{3a^2-3}

Let us simplify the numerator and denominator separately.

The numerator is given as 2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,

=2(a^2-2a+1)

Now, a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes 2(a-1)(a-1)

The denominator is given as: 3a^2-3

Factoring out 3, we get

3(a^2-1)

Now, a^2-1 is of the form a^2-b^2=(a-b)(a+b)

So, a^2-1=(a-1)(a+1)

Therefore, the denominator becomes 3(a-1)(a+1)

Now, the given expression is simplified to:

\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}

There is (x-1) in the numerator and denominator. We can cancel them only if x\ne1 as for x=1, the given expression is undefined.

Now, cancelling the like terms considering x\ne1, we get:

\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}

Therefore, the simplified form is \dfrac{2(x-1)}{3(x+1)}

The simplification is true only if  x\ne1. So, x =1 is the excluded value for the given expression.

8 0
3 years ago
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