Find the coordinates of the points of intersection of the parabola y=x^2+3x-4 and the line y=2x+2
1 answer:
You can set the y values equal to each other and solve the system: x^2+3x-4=2x+2 x^2+x-6=0 (x+3)(x-2)=0 x=-3,2 So, these are the x values of the intersection. To get the y values, you can just plug them back into either formula: y=2(-3)+2 y=-4 y2(2)+2 y=6 So the coordinates are (-3,-4) and 2,6).
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23,356 the answer rounded to nearest whole number