Find the coordinates of the points of intersection of the parabola y=x^2+3x-4 and the line y=2x+2
1 answer:
You can set the y values equal to each other and solve the system:
x^2+3x-4=2x+2
x^2+x-6=0
(x+3)(x-2)=0
x=-3,2
So, these are the x values of the intersection. To get the y values, you can just plug them back into either formula:
y=2(-3)+2
y=-4
y2(2)+2
y=6
So the coordinates are (-3,-4) and 2,6).
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Answer:
Image D is correct.
Answer:
x^2 + 2x +1 = 2x + 2
Step-by-step explanation:
(x+1) = 2
multiplying both sides by x +1
(x +1) (x+1) = 2 (x+1)
x^2 + 2x +1 = 2x + 2
3y - y + 8 - 2 = 20
3y - y = 2y
8 - 2 = 6
2y + 6 = 20
2y = 20 - 6
y = 10 - 3
the answer is: y = 7
4/5 of 55= 44 That’s the answer
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