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Vera_Pavlovna [14]
2 years ago
7

Find the coordinates of the points of intersection of the parabola y=x^2+3x-4 and the line y=2x+2

Mathematics
1 answer:
lana [24]2 years ago
6 0
You can set the y values equal to each other and solve the system:

x^2+3x-4=2x+2
x^2+x-6=0
(x+3)(x-2)=0
x=-3,2

So, these are the x values of the intersection. To get the y values, you can just plug them back into either formula:

y=2(-3)+2
y=-4

y2(2)+2
y=6

So the coordinates are (-3,-4) and 2,6).
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Did you ever get the answer to this?

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postnew [5]

Answer:

(-1, 2/3).

Step-by-step explanation:

Taking the derivative of f, we get f' = x^2 - 1 = 0.  Thus, x = -1 and x = +1.

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2 years ago
What is the area of the rectangle with the given dimensions? *
exis [7]

Given:

The dimensions of a rectangle are 2x-5 and 3x+3.

To find:

The expression that represents the area of the rectangle in simplest terms.

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Area of a rectangle is:

Area=Length\times Width

The dimensions of a rectangle are 2x-5 and 3x+3. So, the area of the given rectangle is:

Area=(2x-5)\times (3x+3)

Area=2x(3x)+2x(3)-5(3x)-5(3)

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Area=6x^2-9x-15

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4 0
3 years ago
Can someone help me on this Quiz
Gnesinka [82]

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5 0
3 years ago
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Trigonometry
schepotkina [342]

The area of the triangle ABC is 207.5 square units.

Explanation:

The measurements of the sides of the triangle are AB=19, AC=24 and m\angle A=65^{\circ}

We need to determine the area of the triangle ABC.

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

{Area}=\frac{1}{2} b c \sin A

where b=19, c=24 and m\angle A=65^{\circ}

Substituting these values in the above formula, we get,

{Area}=\frac{1}{2}(19)(24)  \sin 65^{\circ}

Simplifying the values, we get,

{Area}=\frac{1}{2}(456) (0.91)

{Area}=\frac{1}{2}(414.96)

{Area}=207.48

Rounding off to the nearest tenth, we get,

{Area}=207.5

Thus, the area of the triangle ABC is 207.5 square units.

5 0
2 years ago
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