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3 years ago

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Some questions make use of the Interactive Graphing Tool to draw a basic graph and then use interactions to

1 answer:

Setler79 [48]3 years ago

3 0

Answer:

Step-by-step explanation:

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1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

<u>Step-by-step explanation:</u>

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

4 years ago

Can someone help me with this..?? look at picture

Lapatulllka [165]

Answer:

pi x m^3

Step-by-step explanation:

6 0

3 years ago

iragen [17]

Answer:

{(-1,4),(2,7),(3,7)}

Step-by-step explanation:

This is the only answer with inputs that are not repeated, therefore it is the answer.

6 0

3 years ago

What is the discriminant of the polynomial?<br>2x^2+5x-8<br>

12345 [234]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's find the discriminant (D) of the given polynomial ~

Let's compare the given quadratic expression with general expression ~

$\boxed{ \boxed{ \sf {ax}^{2} +b x + c }}$

we get ;

$\sf \: a = 2$
$\sf \: b = 5$
$\sf \: c = - 8$

Now, use the following formula :

$\qquad \sf \dashrightarrow \: D = b² - 4ac$

$\qquad \sf \dashrightarrow \: D = (5) {}^{2} - (4 \times 2 \times ( - 8))$

$\qquad \sf \dashrightarrow \: D = 25 - ( - 64)$

$\qquad \sf \dashrightarrow \: D = 25 + 64$

$\qquad \sf \dashrightarrow \: D = 89$

Therefore, discriminant of the given quadratic expression is 89

5 0

3 years ago

Please help me that’s would be great and I promise to mark brainlest!!

defon

Option A is correct.

If we evaluate the function at $x=0$ , i.e. at the beginning, we have

$f(0)=75 \cdot 2^0 = 75 \cdot 1 = 75$

with each minute, you multiply the current number of cell by 2, so they double every minute.

Option B is incorrect, because if the number of cells increases by 2 every minute, the function would be

$f(x) = 75 + 2k$

Option C is incorrect, because after one minute (i.e. when x=1) we have

$f(1) = 75\cdot 2^1 = 75 \cdot 2 = 150$

cells, so 75 is not the number of cells after one minute

Option D is incorrect in both the initial value and the behaviour of the function

6 0

3 years ago