4 years ago

Which of the following relations is a function?

Mathematics

1 answer:

mafiozo [28]4 years ago

8 0

Answer:

Step-by-step explanation:

A. The input 0 = the outputs 4, 3

B. The input 6 = the outputs 1, 2

C. No inputs have more than one output

D. The input -1 = the outputs 3, 5

Functions can only have one output for each input. So C is the only function.

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2(2x-3) + 3(x + 1) = 5x +2

Lerok [7]

X=5/2 , remove parentheses , collect like terms, move terms , collect like terms and calculate the sum , then divide both sides by 2 , hope this helped broski

5 0

3 years ago

Read 2 more answers

Explain how to solve 3^x-4=6 using the change of base formula log base b of y equals log y over log b. include the solution for

Alexxandr [17]

Answer:

x = log 10/log 3

Step-by-step explanation:

3^x - 4 = 6

3^x = 10

We take log base 3 of both sides since log_3 3^x is simply x.

log_3 3^x = log_3 10

x = log_3 10

We have an answer for x, but it is a log base 3. We want log base 10.

Now we use the change of base formula.

log_b y = log y/log b

x = log 10/log 3

7 0

3 years ago

3√6/√15<br> Solve it using radicals please!!!

algol [13]

Answer:

3√10/5

Step-by-step explanation:

$\frac{3\sqrt{6} }{\sqrt{15} }$

Rationalize √15

$\hookrightarrow \frac{3\sqrt{6} }{\sqrt{15}}\times\frac{\sqrt{15} }{\sqrt{15} } \\\\\hookrightarrow \frac{3\sqrt{6} \times\sqrt{15} }{15} \\\\\hookrightarrow \frac{3\sqrt{90}}{15} \\\\\hookrightarrow \frac{3\sqrt{10} }{5} \\\\$